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Question

The Coriolis component of acceleration of a slider moving with velocity V on a link having angular velocity ω is

The correct answer is

2vω

Coriolis Acceleration Explained

The Coriolis acceleration is a component of acceleration that arises in systems where a body moves relative to a rotating frame of reference. It is a crucial concept in the study of kinematics of mechanisms, particularly when dealing with links that rotate while other components slide along them. This acceleration acts perpendicular to both the relative velocity of the body and the angular velocity of the rotating frame.

Consider a slider moving along a link that is simultaneously rotating. The motion of the slider relative to the rotating link combined with the link's angular motion results in this special component of acceleration known as the Coriolis component of acceleration. It is important for accurately analyzing the total acceleration of points in such complex mechanisms.

Slider Velocity and Link Angular Velocity

In the given problem, we have a slider moving with a velocity \(V\). This \(V\) represents the relative velocity of the slider with respect to the link it is sliding on. The link itself possesses an angular velocity, denoted by \(\omega\). This \(\omega\) signifies how fast the link is rotating.

The Coriolis acceleration depends directly on both these parameters: the relative speed of the slider and the rate of rotation of the link.

Formula for Coriolis Acceleration

For a point (like a slider) moving with a relative velocity \(v_{rel}\) with respect to a rotating body (like a link) having an angular velocity \(\omega\), the magnitude of the Coriolis component of acceleration (\(a_c\)) is given by the formula:

\[a_c = 2 v_{rel} \omega\]

Here:

  • \(v_{rel}\) is the relative velocity of the slider along the link.
  • \(\omega\) is the angular velocity of the link.
  • The factor of '2' is a fundamental part of the Coriolis acceleration formula.

Calculating Coriolis Component

Given that the velocity of the slider is \(V\) (which is its relative velocity, \(v_{rel} = V\)) and the angular velocity of the link is \(\omega\), we can directly substitute these values into the Coriolis acceleration formula:

\[a_c = 2 V \omega\]

Therefore, the Coriolis component of acceleration of a slider moving with velocity \(V\) on a link having angular velocity \(\omega\) is \(2V\omega\).

This result is fundamental in the kinematic analysis of mechanisms involving relative motion on rotating components, such as quick return mechanisms or radial engines.

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Important Questions from Acceleration Analysis

  1. A solid disc of radius r rolls without slipping on the horizontal floor with angular velocity ω and angular acceleration α. The magnitude of acceleration of the point of contact on the disc is

  2. In Klein's construction for reciprocating engine mechanism, the scale of acceleration diagram will be

  3. If a block slides outward on a link at a uniform rate of 30 m/s, while the link is rotating at a constant angular velocity of 50 rad/s counter clockwise, the Coriolis component of acceleration is ___________ m/s2.

  4. A point on a rigid flywheel of radius 750 mm undergoes a uniform linear acceleration of 3 m/s2. The flywheel’s angular acceleration is

  5. The magnitude of coriolis component of acceleration is (Where v = velocity, ? = angular velocity)

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