The natural line width of a spectral line is determined by the finite lifetime of the excited atomic state. This relationship is governed by the Heisenberg uncertainty principle, which states that the product of the uncertainty in energy ($\Delta E$) and the uncertainty in time ($\Delta t$) is at least proportional to the reduced Planck constant ($\hbar$):
$ \Delta E \Delta t \gtrsim \frac{\hbar}{2} $
In this context, the lifetime of the state ($\tau$) serves as the time uncertainty ($\Delta t$). Therefore, the natural line width (minimum energy uncertainty $\Delta E$) can be approximated as:
$ \Delta E \approx \frac{\hbar}{\tau} $
We are given:
Applying the formula:
$ \Delta E \approx \frac{\hbar}{\tau} $
Substituting the values:
$ \Delta E \approx \frac{6.58 \times 10^{-16} \text{ eV·s}}{1 \times 10^{-9} \text{ s}} $
Calculating the energy width:
$ \Delta E \approx 6.58 \times 10^{-7} \text{ eV} $
The calculated natural line width is approximately $6.58 \times 10^{-7}$ eV. We must select the option that best represents the order of magnitude of this result.
The available options are:
Comparing our calculated value ($6.58 \times 10^{-7}$ eV) to the options, it is found to be closest in order of magnitude to $10^{-8}$ eV.
The wavefunction of a particle in one dimension is given by
$\psi(x) = \begin{cases} M, & -a < x < a \\ 0, & \text{otherwise.} \end{cases}$
Here $M$ and $a$ are positive constants. If $\phi(p)$ is the corresponding momentum space wavefunction, which one of the following plots best represents $|\phi(p)|^2$ ?