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Question

The length of a diagonal of a rectangular park is 25 meters, and that of one of its sides is 15 meters. Find the perimeter of the park.

The correct answer is
70 meters

Rectangular Park Perimeter Calculation

We are given a rectangular park with the following information:

  • Diagonal length, d = 25 meters
  • Length of one side, l = 15 meters

We need to find the perimeter of the park.

Finding the Other Side Length

In a rectangle, the diagonal, length, and width form a right-angled triangle. We can use the Pythagorean theorem: $l^2 + w^2 = d^2$, where w is the width (the other side).

  1. Substitute the known values: ${15}^2 + w^2 = {25}^2$.
  2. Calculate the squares: $225 + w^2 = 625$.
  3. Isolate $w^2$: $w^2 = 625 - 225$.
  4. Calculate $w^2$: $w^2 = 400$.
  5. Find the width w by taking the square root: $w = \sqrt{400}$.
  6. Result: $w = 20$ meters.

Calculating the Perimeter

The perimeter of a rectangle is calculated using the formula: Perimeter = $2 \times (length + width)$.

  1. Substitute the side lengths we found: Perimeter = $2 \times (15 + 20)$.
  2. Add the lengths: Perimeter = $2 \times (35)$.
  3. Calculate the final perimeter: Perimeter = 70 meters.

Therefore, the perimeter of the rectangular park is 70 meters.

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Important Questions from Mensuration 2D (Notes)

  1. Find the area of a quadrilateral ABCD whose area is twice the area of a triangle PQR. The sides of triangle PQR are in the ratio 4:5:6 and the perimeter of the triangle is 90 cm (use $\sqrt{7} = 2.6$).
  2. Find the area of a regular hexagon whose side measures $14\sqrt{3}$ cm.
  3. Find the perimeter of the semi-circle of radius 21 cm.
    $\left(\text{Take } \pi = \frac{22}{7}\right)$
  4. If the area of an equilateral triangle is given as $900 \text{ m}^2$, then what is its perimeter?
  5. The difference between two parallel sides of a trapezium is 9 cm. The perpendicular distance between them is 52 cm. If the area of the trapezium is 988 \(cm^2\), find the lengths of the parallel sides (in cm).

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