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The integral

\(\frac{1}{2\pi i}\oint\frac{\exp\left[\frac{z}{2}\left(t-\frac{1}{t}\right)\right]}{t^{n+1}}\,dt\),

where \(n\) is an integer and the closed contour is a circle enclosing the origin, can be used to :

This question was previously asked in
MH SET 2023 Paper 2 Computer Science and Applications Question Paper (26-Mar-2023)
The correct answer is

generate Bessel’s functions of first kind

The function \(g(z,t)=\exp\left[\frac{z}{2}\left(t-\frac{1}{t}\right)\right]\) is the generating function of the Bessel functions of the first kind: \(g(z,t)=\sum_{n=-\infty}^{\infty}J_{n}(z)\,t^{n}\), a Laurent series in \(t\) about \(t=0\).

By the Laurent coefficient formula, the coefficient of \(t^{n}\) is \(\frac{1}{2\pi i}\oint\frac{g(z,t)}{t^{n+1}}dt\) around any circle enclosing the origin. Hence the given integral equals \(J_{n}(z)\).

The other families have different generating functions: Hermite \(e^{2xt-t^{2}}\), Legendre \((1-2xt+t^{2})^{-1/2}\), and associated Legendre functions are obtained from the Legendre generating function by differentiation, none of which matches this exponential.

Check: setting \(n=0\) and expanding to lowest order in \(z\) gives \(J_{0}(z)\approx 1-\frac{z^{2}}{4}\), the known series start of the Bessel function of order zero.

Hence, generate Bessel’s functions of first kind.

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