The HCF of 448 and 336 is _______ times the HCF of 48 and 36.
28/3
We need to find how many times the HCF of 48 and 36 is contained within the HCF of 448 and 336.
1. Finding the HCF of 448 and 336
Using the Euclidean algorithm:
- 448 = 336 * 1 + 112
- 336 = 112 * 3 + 0
Therefore, HCF(448, 336) = 112.
2. Finding the HCF of 48 and 36
Using the Euclidean algorithm:
- 48 = 36 * 1 + 12
- 36 = 12 * 3 + 0
Therefore, HCF(48, 36) = 12.
3. Comparing the HCFs
We need to find the ratio of HCF(448, 336) to HCF(48, 36):
112 / 12 = 28/3
Therefore, the HCF of 448 and 336 is 28/3 times the HCF of 48 and 36.
Important Questions from Time and work
In a circular race on a track of length 2000 m, X and Y start from the same point at the same time in opposite directions at the speeds of 15 km/h and 33 km/h, respectively. After how much time will they meet next?
Which of the following option figures will complete the pattern in the figure given below?
A has completed two-third of a job in 8 days, and B completes the rest of the job in 20 days. In how many days can they together complete the job?
The smallest 4-digit prime number is:
If Anand can do a piece of work in 9 days and Vinod can complete the same work in 6 days, then in how many days will both of them complete it together?
