924
We are given that when number p is divided by 55, the quotient is 4 and the remainder is 0.
Using the division algorithm, dividend = divisor × quotient + remainder, we can find p:
\(p = 55 \times 4 + 0\)
\(p = 220\)
For any two positive integers, the product of the numbers is equal to the product of their Highest Common Factor (HCF) and Least Common Multiple (LCM).
The formula is: HCF(p, q) × LCM(p, q) = p × q
We are given:
Substitute the known values into the formula:
\(44 \times 4620 = 220 \times q\)
Now, solve for q:
\(q = \frac{44 \times 4620}{220}\)
To simplify, we can divide 44 by 220:
\(\frac{44}{220} = \frac{1}{5}\)
So the equation becomes:
\(q = \frac{1}{5} \times 4620\)
\(q = \frac{4620}{5}\)
\(q = 924\)
The calculated value for q is 924. Based on the provided options, the correct answer is Option C.
The HCF of \(x\) and \(y\) is \(H\). Consider the following statements in respect of the HCF of \(p=\frac{x^3 + y^3}{x^2-xy+y^2}\) and \(q=\frac{x^3-y^3}{x^2+xy+y^2}\) :
I. The HCF of \(p\) and \(q\) can be \(H\).
II. The HCF of \(p\) and \(q\) can be \(2H\).
Which of the statements given above is/are correct?
Let \(N\) be the least positive multiple of 11 that leaves a remainder of 5 when divided by 6, 12, 15, 18. Which one of he following is correct?
Let \(n\) be a natural number. The HCF of \(n, n + 10\) is 10. If the LCM is \(x\) (a 2-digit number), then how many values of \(x\) are possible?
The HCF and LCM of two numbers are 12 and 72, respectively. If the ratio of the two numbers is 2 ∶ 3, then the larger of the two numbers is:
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Joseph visits the club on every 5 th day, Harsh visits on every 24 th day, while Sumit visits on every 9 th day. If all three of them met at the club on a Sunday, then on which day will all three of them meet again?
What is the least number which when divided by 12,20 and 24 leaves in each case a remainder of 8?
Which of the following is a pair of co-primes?