This question requires applying Chargaff's rules to determine the percentage of Adenine (A) in a DNA genome, given the Guanine-Cytosine (GC) content.
Chargaff's rules are fundamental principles of DNA composition:
Given GC Content: The genome has 60% GC content. This means the combined percentage of Guanine and Cytosine is 60%.
$G + C = 60\%$
Calculate Individual G and C Percentages: Since $G = C$, we can find the percentage of each base by dividing the total GC content by 2.
$G = C = \frac{60\%}{2} = 30\%$
Calculate Remaining Base Percentage (A + T): The total percentage of Adenine and Thymine is the remainder after accounting for GC content.
$A + T = 100\% - (G + C)$
$A + T = 100\% - 60\% = 40\%$
Calculate Adenine Percentage: According to Chargaff's rules, $A = T$. Therefore, we divide the combined percentage of A + T by 2 to find the percentage of Adenine.
$A = \frac{A + T}{2}$
$A = \frac{40\%}{2} = 20\%$
The percentage of Adenine (A) in this genome is 20%.
The genome of a diploid species has 10 genes. In a population of this species, if each gene has two unique alleles, then the number of possible unique genotypes in this population is ______
(Answer in integer)