1:2:1
This problem involves basic Mendelian genetics, specifically focusing on incomplete dominance.
Let the allele for red flowers be represented by $R$ and the allele for white flowers by $W$. Since the plants are pure-bred, their genotypes are:
The initial cross is between these two pure-bred plants:
$ RR \textit{ (Red)} \times WW \textit{ (White)} $
All offspring in the F1 generation inherit one allele from each parent. Therefore, the genotype of all F1 plants is $RW$.
Due to incomplete dominance, the heterozygous genotype $RW$ results in a blended phenotype, which is pink flowers.
F1 Genotype: $RW$ (all plants)
F1 Phenotype: Pink Flowers
The F1 plants ( $RW$ ) are selfed, meaning they are crossed with themselves:
$ RW \textit{ (Pink)} \times RW \textit{ (Pink)} $
The possible genotypes in the F2 generation can be determined using a Punnett square:
The resulting genotypic ratio is:
$ 1 RR : 2 RW : 1 WW $
Based on incomplete dominance:
Therefore, the phenotypic ratio in the F2 generation is:
$ 1 \textit{ Red} : 2 \textit{ Pink} : 1 \textit{ White} $
The question asks for the proportion of white : pink : red flowers.
Based on the F2 phenotypic ratio, the proportion is:
$ 1 \textit{ (White)} : 2 \textit{ (Pink)} : 1 \textit{ (Red)} $
This corresponds to the ratio 1:2:1.
The genome of a diploid species has 10 genes. In a population of this species, if each gene has two unique alleles, then the number of possible unique genotypes in this population is ______
(Answer in integer)