The final product (D) in the above conversion is
To solve the problem and identify the final product (D) in the given reaction sequence, let's analyze each step.

The starting material is an alkyne, specifically 2-butyne (CH3C≡CCH3).
The first step involves the addition of 1 mole of H2 in the presence of Ni, resulting in partial hydrogenation.
This converts the alkyne to a cis-alkene (A): CH3CH=CHCH3.
The alkene is treated with PhCO3H and H3O+, resulting in an epoxidation and subsequent opening of the epoxide to give a diol, (B):
The structure of (B) is a vicinal diol.
Upon reaction with HIO4, the diol undergoes oxidative cleavage to form carbonyl compounds.
The result is an aldehyde and a ketone.
(C): Acetone (CH3COCH3) and formaldehyde (HCHO).
Finally, the reaction with EtMgBr in Et2O followed by H+ converts formaldehyde to a primary alcohol:
Ethylmagnesium bromide adds to the aldehyde, yielding an alcohol after hydrolysis (D).
This results in 2-butanol (CH3CHOHCH2CH3).
Therefore, the final product (D) is 2-Butanol. It is formed through the Grignard reaction with formaldehyde and subsequent protonation.
Correct Answer: 2-Butanol
Choose the correct statement from the following:
(A). Water has highest density at 4°C
(B). Freezing point of water is 0°C
(C) An Ice cube does not completely dip in water, rather floats on water in a glass.
(D). Addition of common salt reduces freezing point of water.
Choose the correct answer from the options given below: