Simple Cubic Unit Cell Atoms Calculation
The question asks for the number of atoms present in one unit cell of a Simple Cubic (SCC) crystal structure.
Understanding Simple Cubic (SCC) Structure
A Simple Cubic lattice is one of the simplest crystal structures. In this structure:
- Atoms are located only at the eight corners of the cube.
- There are no atoms at the center of the faces or the body center.
Calculating Atoms per SCC Unit Cell
To find the total number of atoms within a single unit cell, we need to consider how much of each corner atom actually belongs to that specific unit cell.
- In a simple cubic structure, each corner atom is shared by 8 adjacent unit cells.
- Therefore, only 1/8th of each corner atom belongs to any single unit cell.
The calculation is as follows:
Number of atoms = (Contribution of atoms at corners)
Number of atoms = (Number of corners) × (Fraction of atom at each corner)
Number of atoms = (8 corners) × (1/8 atom/corner)
Number of atoms = $8 \times \frac{1}{8}$
Number of atoms = $1$
Thus, there is exactly 1 atom per unit cell in a Simple Cubic (SCC) structure.
Conclusion
Based on the structure and the calculation of shared atoms, the number of atoms per unit cell for SCC is 1.
Important Questions from Chemistry (CUET PG) Mixed
The final product (P) is
Consider the following statements with respect to citral
(A). Geranial and Neral are geometrical isomers of citral.
(B). It forms geranic acid on heating with potassium hydrogen sulphate.
(C). It gives 6-methylhept-5-en-2-one on treating with potassium carbonate.
(D). On oxidation with silver oxide it yields Laevulic acid.
Choose the correct answer from the options given below:Which correct sequence of reactions are applied to achieve the following transformation?
Above conversion is carried out using
The final product (D) in the above conversion is
