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Question

The efficiency of a class B amplifier for a supply voltage of $V_{CC} = 24$ V with peak output voltage of $V_L(p) = 6$ V is

The correct answer is
19.63%

Class B Amplifier Efficiency Calculation

This solution calculates the efficiency ($\eta$) of a Class B amplifier using the provided supply voltage ($V_{CC}$) and peak output voltage ($V_L(p)$).

Efficiency Formula for Class B Amplifier

The efficiency of a Class B amplifier is determined by the ratio of AC output power to DC input power. The formula derived from power calculations is:

$ \eta = \frac{\pi V_L(p)}{4 V_{CC}} $

Given Parameters

  • Supply Voltage: $V_{CC} = 24$ V
  • Peak Output Voltage: $V_L(p) = 6$ V

Calculation Steps

  1. Substitute Values: Plug the given values into the efficiency formula.

    $ \eta = \frac{\pi \times 6 \text{ V}}{4 \times 24 \text{ V}} $

  2. Simplify Expression: Reduce the fraction.

    $ \eta = \frac{6\pi}{96} $

    $ \eta = \frac{\pi}{16} $

  3. Calculate Percentage: Convert the fraction to a decimal and then to a percentage.

    $ \eta \approx \frac{3.14159}{16} $

    $ \eta \approx 0.196349 $

    $ \eta \approx 19.63\% $

Conclusion

The calculated efficiency is approximately $19.63\%$. This matches option B.

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Important Questions from Power Amplifier

  1. _______ is usually used in RF power amplifier and in amateur radio.

  2. The collector current of a class C amplifier is _______.

  3. A single stage amplifier employing one active device is powered by a 9 V battery which has a current drain of 20 mA. If load voltage is 3 V at 12 mA, then determine η.

  4. A tuned Class-C amplifier has a power supply voltage of 12 V. What is the ideal peak-to-peak output voltage?
  5. The type of amplifier which exhibits crossover distortion in its output is:
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