The divergence of vector xi +yj + zk is
3
This explanation details the calculation of the divergence for a given vector field.
The divergence is a vector calculus operation that measures the rate at which a vector field flows outwards from a given point. It essentially quantifies the "source" or "sink" strength at that point. If the divergence is positive, it indicates an outward flow (a source); if negative, an inward flow (a sink); and if zero, the flow is incompressible (no net flow in or out).
The vector field provided is:
F = xi + yj + zk
In this vector field:
The divergence of a vector field $F = P(x, y, z)i + Q(x, y, z)j + R(x, y, z)k$ is calculated using the Del operator ($\nabla$) dotted with the vector field:
$\nabla \cdot F = (\frac{\partial}{\partial x}i + \frac{\partial}{\partial y}j + \frac{\partial}{\partial z}k) \cdot (Pi + Qj + Rk) = \frac{\partial P}{\partial x} + \frac{\partial Q}{\partial y} + \frac{\partial R}{\partial z}$
Here, $P = x$. So, $\frac{\partial P}{\partial x} = \frac{\partial}{\partial x}(x) = 1$.
Here, $Q = y$. So, $\frac{\partial Q}{\partial y} = \frac{\partial}{\partial y}(y) = 1$.
Here, $R = z$. So, $\frac{\partial R}{\partial z} = \frac{\partial}{\partial z}(z) = 1$.
The divergence is the sum of these results:
$\nabla \cdot F = \frac{\partial P}{\partial x} + \frac{\partial Q}{\partial y} + \frac{\partial R}{\partial z} = 1 + 1 + 1 = 3$
The divergence of the vector field $F = xi + yj + zk$ is 3.
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