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Question

The distance between two points A and B is covered in 5 ½ hours at a speed of 50 km/hr. If the speed is increased by 5 km/hr, how much time would be saved?

A. 5 minutes

B. 15 minutes

C. 50 minutes

D. 30 minutes

The correct answer is

D

Understanding Time, Speed, and Distance Calculation

This question asks us to calculate the time saved when traveling a certain distance at an increased speed. To solve this, we first need to find the total distance covered. Then, we calculate the time it takes to cover the same distance at the new speed and finally find the difference in time, which is the time saved.

Step 1: Calculate the Distance Between Points A and B

We are given the initial speed and the time taken to cover the distance between points A and B.

  • Initial Speed = 50 km/hr
  • Initial Time = \(5 \frac{1}{2}\) hours

First, let's convert the initial time into a decimal or improper fraction for easier calculation.

\(5 \frac{1}{2} \text{ hours} = 5.5 \text{ hours}\) or \(\frac{11}{2} \text{ hours}\).

The formula relating distance, speed, and time is:

\(\text{Distance} = \text{Speed} \times \text{Time}\)

Using the initial values:

\(\text{Distance} = 50 \, \text{km/hr} \times 5.5 \, \text{hours}\)

\(\text{Distance} = 275 \, \text{km}\)

So, the distance between points A and B is 275 km.

Parameter Value
Initial Speed 50 km/hr
Initial Time 5.5 hours
Calculated Distance 275 km

Step 2: Calculate the New Speed

The question states that the speed is increased by 5 km/hr.

  • Initial Speed = 50 km/hr
  • Increase in Speed = 5 km/hr

New Speed = Initial Speed + Increase in Speed

New Speed = 50 km/hr + 5 km/hr

New Speed = 55 km/hr

Step 3: Calculate the Time Taken at the New Speed

Now we use the calculated distance and the new speed to find the time taken.

  • Distance = 275 km
  • New Speed = 55 km/hr

Using the formula \(\text{Time} = \frac{\text{Distance}}{\text{Speed}}\):

\(\text{New Time} = \frac{275 \, \text{km}}{55 \, \text{km/hr}}\)

\(\text{New Time} = 5 \, \text{hours}\)

So, at the increased speed of 55 km/hr, the journey would take 5 hours.

Parameter Value
Distance 275 km
New Speed 55 km/hr
Calculated New Time 5 hours

Step 4: Calculate the Time Saved

The time saved is the difference between the initial time and the new time.

  • Initial Time = 5.5 hours
  • New Time = 5 hours

\(\text{Time Saved} = \text{Initial Time} - \text{New Time}\)

\(\text{Time Saved} = 5.5 \, \text{hours} - 5 \, \text{hours}\)

\(\text{Time Saved} = 0.5 \, \text{hours}\)

Step 5: Convert Time Saved to Minutes

The options are given in minutes. We need to convert 0.5 hours into minutes.

There are 60 minutes in 1 hour.

\(\text{Time Saved (minutes)} = \text{Time Saved (hours)} \times 60 \, \text{minutes/hour}\)

\(\text{Time Saved (minutes)} = 0.5 \, \text{hours} \times 60 \, \text{minutes/hour}\)

\(\text{Time Saved (minutes)} = 30 \, \text{minutes}\)

Thus, 30 minutes would be saved if the speed is increased by 5 km/hr.

Revision Table: Time, Speed, and Distance Concepts

Concept Formula Units (Example)
Distance Speed × Time km, meters, miles
Speed \(\frac{\text{Distance}}{\text{Time}}\) km/hr, m/s, miles/hr
Time \(\frac{\text{Distance}}{\text{Speed}}\) hours, seconds, minutes

Additional Information: Speed Calculation Tips

  • Always ensure units are consistent when using the formulas (e.g., if speed is in km/hr, time should be in hours and distance in km).
  • Converting between units like hours and minutes (1 hour = 60 minutes) is crucial for time, speed, and distance problems.
  • Increasing speed reduces the time taken for a fixed distance, while decreasing speed increases the time taken.
  • Understanding fractional or decimal time representations (like \(5 \frac{1}{2}\) hours = 5.5 hours) is important.
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Important Questions from Average Speed

  1. A car covers the first 41 km of its journey in 45 min and covers the remaining 23 km in 35 min. What is the average speed (in m/sec) of the car?

  2. Akhil drives a car from his home to office at an average speed of 50 km/h and reaches office 10 minutes early. But one day due to some problem with the car, he could drive at an average speed of 30 km/h only and reached office 10 minutes late. How far is his office from home ?

  3. During a flight of 900 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 300 km/h and the time of flight increased by 30 min. The original duration of the flight was :

  4. If a man travels from A to B at a speed of 50 km/h and returns by increasing his speed by 40%, then find his average speed (to 2 decimal places) for both the trips.

  5. A man travels a distance of 420 km by train which moves at the speed of 75 km/h and returns back by car at the speed of 50 km/h. Find his average speed for the whole journey.

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