The distance between two points A and B is covered in 5 ½ hours at a speed of 50 km/hr. If the speed is increased by 5 km/hr, how much time would be saved? A. 5 minutes B. 15 minutes C. 50 minutes
D
This question asks us to calculate the time saved when traveling a certain distance at an increased speed. To solve this, we first need to find the total distance covered. Then, we calculate the time it takes to cover the same distance at the new speed and finally find the difference in time, which is the time saved.
We are given the initial speed and the time taken to cover the distance between points A and B.
First, let's convert the initial time into a decimal or improper fraction for easier calculation.
\(5 \frac{1}{2} \text{ hours} = 5.5 \text{ hours}\) or \(\frac{11}{2} \text{ hours}\).
The formula relating distance, speed, and time is:
\(\text{Distance} = \text{Speed} \times \text{Time}\)
Using the initial values:
\(\text{Distance} = 50 \, \text{km/hr} \times 5.5 \, \text{hours}\)
\(\text{Distance} = 275 \, \text{km}\)
So, the distance between points A and B is 275 km.
| Parameter | Value |
|---|---|
| Initial Speed | 50 km/hr |
| Initial Time | 5.5 hours |
| Calculated Distance | 275 km |
The question states that the speed is increased by 5 km/hr.
New Speed = Initial Speed + Increase in Speed
New Speed = 50 km/hr + 5 km/hr
New Speed = 55 km/hr
Now we use the calculated distance and the new speed to find the time taken.
Using the formula \(\text{Time} = \frac{\text{Distance}}{\text{Speed}}\):
\(\text{New Time} = \frac{275 \, \text{km}}{55 \, \text{km/hr}}\)
\(\text{New Time} = 5 \, \text{hours}\)
So, at the increased speed of 55 km/hr, the journey would take 5 hours.
| Parameter | Value |
|---|---|
| Distance | 275 km |
| New Speed | 55 km/hr |
| Calculated New Time | 5 hours |
The time saved is the difference between the initial time and the new time.
\(\text{Time Saved} = \text{Initial Time} - \text{New Time}\)
\(\text{Time Saved} = 5.5 \, \text{hours} - 5 \, \text{hours}\)
\(\text{Time Saved} = 0.5 \, \text{hours}\)
The options are given in minutes. We need to convert 0.5 hours into minutes.
There are 60 minutes in 1 hour.
\(\text{Time Saved (minutes)} = \text{Time Saved (hours)} \times 60 \, \text{minutes/hour}\)
\(\text{Time Saved (minutes)} = 0.5 \, \text{hours} \times 60 \, \text{minutes/hour}\)
\(\text{Time Saved (minutes)} = 30 \, \text{minutes}\)
Thus, 30 minutes would be saved if the speed is increased by 5 km/hr.
| Concept | Formula | Units (Example) |
|---|---|---|
| Distance | Speed × Time | km, meters, miles |
| Speed | \(\frac{\text{Distance}}{\text{Time}}\) | km/hr, m/s, miles/hr |
| Time | \(\frac{\text{Distance}}{\text{Speed}}\) | hours, seconds, minutes |
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