Let Ayushi's present age be $A$ years and Nidhi's present age be $N$ years.
According to the problem statement:
Now we have a system of two linear equations:
To find $N$, we can subtract Equation (1) from Equation (2):
$(A + N) - (A - N) = 40 - 26$ $A + N - A + N = 14$ $2N = 14$ $N = \frac{14}{2}$ $N = 7$Therefore, Nidhi's present age is 7 years.
To verify, we can find Ayushi's age using Equation (2): $A + 7 = 40 \implies A = 33$. The difference is $33 - 7 = 26$, and 5 years ago their ages were $33-5=28$ and $7-5=2$, summing to $28+2=30$. The conditions are met.
The ages of two persons P and Q are in the ratio 5 : 7. Eight years ago, the ratio of P and Q was 7 : 13. The present ages of P and Q, respectively, are:
One year ago, the ratio of the ages of A and B was 4 : 3. The ratio of their ages, after 7 years from now, will be 9 : 7. What is the present age (in years) of B?
In 8 years, Subhash will be 3 times as old as he is now. After how many years will Subhash be 5 times as old as he is now?
The average ages of parents and two children are 30 years and 8 years respectively. The average age of the family is
A. 16 years
B. 19 years
C. 18 years
D. 17 years
A father is presently 3 times his daughter’s age. After 10 years he will be twice as old as her. Find the daughter’s present age.