Let Ayushi's present age be $A$ years and Nidhi's present age be $N$ years.
According to the problem statement:
Now we have a system of two linear equations:
To find $N$, we can subtract Equation (1) from Equation (2):
$(A + N) - (A - N) = 40 - 26$ $A + N - A + N = 14$ $2N = 14$ $N = \frac{14}{2}$ $N = 7$Therefore, Nidhi's present age is 7 years.
To verify, we can find Ayushi's age using Equation (2): $A + 7 = 40 \implies A = 33$. The difference is $33 - 7 = 26$, and 5 years ago their ages were $33-5=28$ and $7-5=2$, summing to $28+2=30$. The conditions are met.
The ratio of the ages of A and B, four years ago, was 4 : 5. Eight years from now, the ratio of the ages of A and B will be 11 : 13. What is the sum of their present ages?
The ratio of the present ages of A and B is 8 : 9. After 9 years, this ratio will become 19 : 21. C is 3 years younger to B. What is the present (in years) of C?
The ratio of the ages of A and B 8 years ago was 2 : 3. Four years ago, the ratio of their ages was 5 : 7. What will be the ratio of their ages 8 years from now?
The ratio of the present age of father to that of his son is 7 : 2. If after 10 years the ratio of their ages will become 9 : 4, then the present age of the father is:
The ages of two persons P and Q are in the ratio 5 : 7. Eight years ago, the ratio of P and Q was 7 : 13. The present ages of P and Q, respectively, are: