Let $A$ represent Ayushi's present age and $N$ represent Nidhi's present age.
$A - N = 14$ (Equation 1)
$(A - 5) + (N - 5) = 60$
$A + N - 10 = 60$
$A + N = 70$ (Equation 2)
We now have a system of two linear equations:
To find Nidhi's age ($N$), we can subtract Equation 1 from Equation 2:
$(A + N) - (A - N) = 70 - 14$
$A + N - A + N = 56$
$2N = 56$
$N = \frac{56}{2}$
$N = 28$
Nidhi's present age is 28 years.
Using Equation 1: $A - 28 = 14 \implies A = 14 + 28 = 42$. Ayushi's age is 42.
Check ages 5 years ago: Ayushi was $42 - 5 = 37$, Nidhi was $28 - 5 = 23$.
Sum of ages 5 years ago: $37 + 23 = 60$. The conditions are satisfied.
Nidhi's present age is 28 years.
The ratio of the ages of A and B, four years ago, was 4 : 5. Eight years from now, the ratio of the ages of A and B will be 11 : 13. What is the sum of their present ages?
The ratio of the present ages of A and B is 8 : 9. After 9 years, this ratio will become 19 : 21. C is 3 years younger to B. What is the present (in years) of C?
The ratio of the ages of A and B 8 years ago was 2 : 3. Four years ago, the ratio of their ages was 5 : 7. What will be the ratio of their ages 8 years from now?
The ratio of the present age of father to that of his son is 7 : 2. If after 10 years the ratio of their ages will become 9 : 4, then the present age of the father is:
The ages of two persons P and Q are in the ratio 5 : 7. Eight years ago, the ratio of P and Q was 7 : 13. The present ages of P and Q, respectively, are: