Let $A$ represent Ayushi's present age and $N$ represent Nidhi's present age.
$A - N = 14$ (Equation 1)
$(A - 5) + (N - 5) = 60$
$A + N - 10 = 60$
$A + N = 70$ (Equation 2)
We now have a system of two linear equations:
To find Nidhi's age ($N$), we can subtract Equation 1 from Equation 2:
$(A + N) - (A - N) = 70 - 14$
$A + N - A + N = 56$
$2N = 56$
$N = \frac{56}{2}$
$N = 28$
Nidhi's present age is 28 years.
Using Equation 1: $A - 28 = 14 \implies A = 14 + 28 = 42$. Ayushi's age is 42.
Check ages 5 years ago: Ayushi was $42 - 5 = 37$, Nidhi was $28 - 5 = 23$.
Sum of ages 5 years ago: $37 + 23 = 60$. The conditions are satisfied.
Nidhi's present age is 28 years.
The ages of two persons P and Q are in the ratio 5 : 7. Eight years ago, the ratio of P and Q was 7 : 13. The present ages of P and Q, respectively, are:
One year ago, the ratio of the ages of A and B was 4 : 3. The ratio of their ages, after 7 years from now, will be 9 : 7. What is the present age (in years) of B?
In 8 years, Subhash will be 3 times as old as he is now. After how many years will Subhash be 5 times as old as he is now?
The average ages of parents and two children are 30 years and 8 years respectively. The average age of the family is
A. 16 years
B. 19 years
C. 18 years
D. 17 years
A father is presently 3 times his daughter’s age. After 10 years he will be twice as old as her. Find the daughter’s present age.