This problem requires calculating the principal amount (the initial investment) based on the difference between compound interest (CI) and simple interest (SI) earned over two years.
The difference between compound interest and simple interest for a principal amount 'P' invested for 2 years at a rate 'r' (in decimal form) is given by the formula:
Difference = $P \times r^2$
We are given:
Now, we substitute the known values into the formula:
$470 = P \times (0.10)^2$
Calculate the square of the rate:
$470 = P \times 0.01$
To find the principal amount (P), rearrange the equation:
$P = \frac{470}{0.01}$
Perform the division:
$P = 470 \times 100$
$P = 47000$
Therefore, the amount invested is Rs. 47000.
The compound interest on a certain sum for 3 years at 8% per annum is Rs. 1,94,784. What is the simple interest on the $\frac{9}{10}$ part of the sum for the same time but at a rate of interest per annum which is $1\frac{1}{2}$ time the rate of interest per annum as applicable for compound interest?