The problem requires finding the principal amount (P) invested, given the difference between compound interest (CI) and simple interest (SI) over 2 years.
We are given:
The formula for the difference between compound interest and simple interest for 2 years is:
$ \text{Difference} = P \times \left(\frac{R}{100}\right)^2 $
Substitute the given values into the formula:
$ 945 = P \times \left(\frac{15}{100}\right)^2 $
Simplify the rate fraction:
$ \frac{15}{100} = \frac{3}{20} $
Now, calculate the square of the fraction:
$ \left(\frac{3}{20}\right)^2 = \frac{9}{400} $
The equation becomes:
$ 945 = P \times \frac{9}{400} $
To find the principal amount (P), rearrange the equation:
$ P = 945 \times \frac{400}{9} $
Calculate the value of P:
$ P = \frac{945}{9} \times 400 $
$ P = 105 \times 400 $
$ P = 42000 $
Therefore, the amount invested was Rs. 42,000.
The compound interest on a certain sum for 3 years at 8% per annum is Rs. 1,94,784. What is the simple interest on the $\frac{9}{10}$ part of the sum for the same time but at a rate of interest per annum which is $1\frac{1}{2}$ time the rate of interest per annum as applicable for compound interest?