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Question

The current population of the town is 68,000. The population increases by 10 percent in the first year and decreases by 5% in the second year. Find the population after 2 years.

The correct answer is

71,060

Given:

The current population of the town is 68,000.

The population increases by 10% in the first year and decreases by 5% in the second year.

Calculation:

After 10% increase, the new population ⇒ 68000 + (68000 × 10/100) = 68000 + 6800 = 74800

In the second year, the population decreases by 5%.

So, after 5% decrease, the new population ⇒ 74800 × 95/100 = 71060

∴ The population after 2 years is 71,060.

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Important Questions from Percentage

  1. In an examination, 25% of the candidates failed in Mathematics and 12% failed in English. If 10% of the candidates failed in both the subjects and 292 candidates passed in both the subjects, which one of the following is the number of total candidates appeared in the examination?

  2. What is the value of 9% of 5500 + 2.4% of 1100 - 40% of 1600?

  3. Population of a village is 7960 in which 4660 are female. If in that village 60% are literate in which 70% female are literate, then what is the number of literate male ?

  4. The numbers of students of three classes of a school are in the ratio 4 : 5 : 6. If numbers of students in these classes increase by 25%, 20% and 25% respectively, then ratio of numbers of students will become:

  5. In an examination, Ram obtained 20 % more than Ashok but 10% less than Rajesh. If the marks obtained by Ashok is 1080. Then the Percentage marks obtained by Rajesh if the full marks is 2000 ;

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