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Question

The current population of the town is 68,000. The population increases by 10 percent in the first year and decreases by 5% in the second year. Find the population after 2 years.

The correct answer is

71,060

Given:

The current population of the town is 68,000.

The population increases by 10% in the first year and decreases by 5% in the second year.

Calculation:

After 10% increase, the new population ⇒ 68000 + (68000 × 10/100) = 68000 + 6800 = 74800

In the second year, the population decreases by 5%.

So, after 5% decrease, the new population ⇒ 74800 × 95/100 = 71060

∴ The population after 2 years is 71,060.

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Important Questions from Percentage

  1. By how much is 50% of 60 greater than 30% of 40?
  2. A fruit seller had some apples. He sells 40% of those apples and still has 240 apples. How many apples did he originally have?
  3. In an election between two candidates, 75% of the voters cast their votes. 2% of the votes cast were declared invalid. A candidate got 9261 votes which were 75% of the total valid votes. The total number of voters enrolled in that election was:
  4. The population of a district is 328000, out of which 164000 are males. 24% of the population is literate. If 34% males are literate, then what percentage of females are literate?
  5. A number, when decreased by 6%, gives 3760. The number is:
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