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Question

The current population of the town is 68,000. The population increases by 10 percent in the first year and decreases by 5% in the second year. Find the population after 2 years.

The correct answer is

71,060

Given:

The current population of the town is 68,000.

The population increases by 10% in the first year and decreases by 5% in the second year.

Calculation:

After 10% increase, the new population ⇒ 68000 + (68000 × 10/100) = 68000 + 6800 = 74800

In the second year, the population decreases by 5%.

So, after 5% decrease, the new population ⇒ 74800 × 95/100 = 71060

∴ The population after 2 years is 71,060.

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Important Questions from Percentage

  1. Radha saves 25% of her income. If her expenditure increases by 20% and her income increases by 29%, then her savings increase by;

  2. The income of A is 45% more than the income of B and the income of C is 60% less than the sum of the incomes of A and B. The income of D is 20% more than that of C. If the difference between the incomes of B and D is Rs. 13200, then the income (in Rs.) of C is:

  3. The price of cooking oil increased by 25%. Find by how much percentage a family must reduce its consumption in order to maintain the same budget.

  4. The population of a city increased by 30% in the first year and decreased by 15% in the next year. If the present population is 11,050 then population 2 years ago was:

  5. The income of A is 30% less than the income of B and the income of B is 137.5% more than that of C. If the income of A is Rs. 28500 less than that of B, then the income (in Rs.) of C is:

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