The correct statement for peroxydisulfuric and dithionic acids from the following, is:
The question asks us to identify the correct statement comparing the number of O-H bonds in peroxydisulfuric acid and dithionic acid.
Let's first look at the chemical formulas and structures of these two acids.
Peroxydisulfuric acid:
Let's count the O-H bonds in peroxydisulfuric acid from its structure:
$\text{H}\textbf{-O-S(=O)}_2\text{-O-O-S(=O)}_2\textbf{-O-H}$
There are two hydroxyl (-O-H) groups, one attached to each sulfur atom. Therefore, peroxydisulfuric acid has two O-H bonds.
Dithionic acid:
Let's count the O-H bonds in dithionic acid from its structure:
$\text{H}\textbf{-O-S(=O)}_2\text{-S(=O)}_2\textbf{-O-H}$
There are two hydroxyl (-O-H) groups, one attached to each $\text{SO}_2$ group. Therefore, dithionic acid has two O-H bonds.
Based on the structural analysis:
Therefore, both peroxydisulfuric acid and dithionic acid have two O-H bonds each.
Let's evaluate the given statements:
The correct statement is that each of these acids has two O-H bonds.
Match the following:
| Reaction | Organo Metallic Catalyst |
| 1. \(CH_2=C H_{2}+\frac{1}{2} O_{2} \rightarrow C H_{3}CHO\) | i. $(Ph_3P)_3RhCl$ |
| 2. \(C H_{3}OH+CO \rightarrow C H_{3}COOH\) | ii. $Co_2(CO)_8$ |
| 3. \(C H_{2}=C H_{2}+2CO+2 H_{2}O \rightarrow C H_{3}C H_{2}CHO\) | iii. $[Rh(Co)_2I_2]^-$ |
| 4.\(C H_{2}=C H_{2}+ H_{2} \rightarrow C H_{3}-C H_{3}\) | iv. $[PdCl_4]^{2-}$ |
Choose the correct answer from the following:
The correct statement(s) for oxygen from the following
A. The ground state for the O atom is 3P1.
B. Both the atom and the diatomic molecule are paramagnetic with two unpaired electrons.
C. The most readily accessible singlet excited state for dioxygen has an empty π* orbital.
is/are
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