The circumcentre of an equilateral triangle is at a distance of 3.2 cm from the base of the triangle. What is the length (in cm) of each of its altitudes?
9.6
In an equilateral triangle, several important points coincide. The circumcenter, which is the center of the circle passing through all three vertices, is the same point as the incenter (center of the inscribed circle), the centroid (intersection of medians), and the orthocenter (intersection of altitudes). This central point lies on each median, altitude, and angle bisector of the triangle.
A key property of the centroid (which is also the circumcenter in an equilateral triangle) is that it divides each median (and thus each altitude) in a specific ratio. The centroid divides the median in the ratio 2:1, measured from the vertex. This means the distance from the vertex to the centroid is twice the distance from the centroid to the base (or the midpoint of the opposite side).
The problem states that the circumcenter is at a distance of 3.2 cm from the base of the equilateral triangle. Since the circumcenter is also the centroid, this distance represents the shorter segment of the altitude, which corresponds to the '1' part of the 2:1 ratio. Let the distance from the circumcenter to the base be $d$. We are given $d = 3.2$ cm.
Let the distance from the vertex to the circumcenter be $D$. According to the 2:1 ratio property, $D = 2 \times d$.
The total length of the altitude, let's call it $h$, is the sum of these two segments:
$\text{Altitude } h = D + d$
Substituting $D = 2d$, we get:
$h = 2d + d = 3d$
We are given $d = 3.2$ cm. Using the formula $h = 3d$, we can calculate the length of the altitude:
$h = 3 \times 3.2 \text{ cm}$
$h = 9.6 \text{ cm}$
Therefore, the length of each altitude of the equilateral triangle is 9.6 cm.
If the distance from the circumcenter to the base is 3.2 cm, this is the segment from the centroid to the base, which is 1/3 of the total altitude. The segment from the vertex to the circumcenter is then $2 \times 3.2 \text{ cm} = 6.4 \text{ cm}$, which is 2/3 of the total altitude. The total altitude is $3.2 \text{ cm} + 6.4 \text{ cm} = 9.6 \text{ cm}$. This confirms our calculation.
| Description | Value |
|---|---|
| Distance from Circumcenter to Base (d) | 3.2 cm |
| Ratio of Circumcenter to Base segment of Altitude | 1 part |
| Total parts in Altitude (Vertex to Base) | 3 parts (2 parts + 1 part) |
| Altitude Length (h) | $3 \times d$ |
| Calculated Altitude Length | $3 \times 3.2 \text{ cm} = 9.6 \text{ cm}$ |
| Property | Description |
|---|---|
| Sides and Angles | All three sides are equal in length. All three interior angles are equal to 60 degrees. |
| Altitudes, Medians, Angle Bisectors | In an equilateral triangle, the altitudes, medians, and angle bisectors from each vertex are the same line segment. |
| Circumcenter, Incenter, Centroid, Orthocenter | These four centers coincide at a single point. |
| Centroid Division Ratio | The centroid divides each median (and thus each altitude) in the ratio 2:1, with the longer segment being from the vertex. |
Understanding the different geometric centers of a triangle is important:
In an equilateral triangle, these four points are the same. In other triangles, they are generally distinct, except for isosceles triangles where they are collinear.
The 2:1 ratio property is specific to the centroid dividing the median. Since the centroid and circumcenter are the same in an equilateral triangle, this ratio applies to the position of the circumcenter on the altitude.
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