If the radius of a circle is decreased by 11% then the total decrease in the area of the circle is given as:
20.79%
Let's break down this problem about the change in the area of a circle when its radius changes. We are given that the radius of a circle is decreased by 11% and we need to find the total decrease in the area of the circle as a percentage.
The area of a circle is calculated using the formula:
$$ A = \pi r^2 $$
where $A$ is the area and $r$ is the radius. When the radius changes, the area changes, but not linearly. Because the radius is squared in the formula, the area changes proportionally to the square of the change in the radius.
Let the original radius of the circle be $r_1$. The radius is decreased by 11%. This means the new radius, $r_2$, will be the original radius minus 11% of the original radius.
So, the new radius is 89% of the original radius.
Using the area formula $A = \pi r^2$:
Substitute the expression for $r_2$ into the formula for $A_2$:
$$ A_2 = \pi (0.89 r_1)^2 $$
Now, we calculate $(0.89)^2$:
$$ (0.89)^2 = 0.89 \times 0.89 = 0.7921 $$
So, the new area is:
$$ A_2 = \pi (0.7921 r_1^2) = 0.7921 (\pi r_1^2) $$
Since $A_1 = \pi r_1^2$, we can write the new area in terms of the original area:
$$ A_2 = 0.7921 A_1 $$
The decrease in area is the original area minus the new area:
$$ \text{Decrease in area} = A_1 - A_2 $$
Substitute $A_2 = 0.7921 A_1$:
$$ \text{Decrease in area} = A_1 - 0.7921 A_1 = (1 - 0.7921) A_1 = 0.2079 A_1 $$
To find the percentage decrease in area, we divide the decrease in area by the original area and multiply by 100%:
$$ \text{Percentage decrease} = \frac{\text{Decrease in area}}{A_1} \times 100\% $$
$$ \text{Percentage decrease} = \frac{0.2079 A_1}{A_1} \times 100\% $$
The $A_1$ terms cancel out:
$$ \text{Percentage decrease} = 0.2079 \times 100\% = 20.79\% $$
So, the total decrease in the area of the circle is 20.79%.
Let's summarize the process:
Let's look at the values:
| Measurement | Expression | Value (relative to original) |
|---|---|---|
| Original Radius ($r_1$) | $r_1$ | $1 r_1$ |
| New Radius ($r_2$) | $r_1 (1 - 0.11)$ | $0.89 r_1$ |
| Original Area ($A_1$) | $\pi r_1^2$ | $\pi r_1^2$ |
| New Area ($A_2$) | $\pi r_2^2 = \pi (0.89 r_1)^2$ | $0.7921 \pi r_1^2$ |
| Decrease in Area | $A_1 - A_2$ | $A_1 - 0.7921 A_1 = 0.2079 A_1$ |
| Percentage Decrease | $\frac{\text{Decrease}}{A_1} \times 100\%$ | $\frac{0.2079 A_1}{A_1} \times 100\% = 20.79\%$ |
The calculated percentage decrease in area is 20.79%.
| Concept | Formula / Idea | Notes |
|---|---|---|
| Area of Circle | $A = \pi r^2$ | Area depends on the square of the radius. |
| Percentage Decrease | $\frac{\text{Original Value} - \text{New Value}}{\text{Original Value}} \times 100\%$ | Always calculated relative to the original value. |
| Radius Decrease by $p\%$ | New Radius $= r (1 - p/100)$ | Radius is $(100-p)\%$ of original. |
| Area Change from Radius Change | $A_{new} = \pi (r_{new})^2$ | Substitute new radius into the area formula. |
When a quantity depends on the square of another quantity, like the area of a circle depending on the square of the radius, a percentage change in the base quantity results in a different percentage change in the derived quantity. If the radius changes by a factor $k$ (i.e., $r_{new} = k \cdot r_{original}$), the new area will be $A_{new} = \pi (k \cdot r_{original})^2 = \pi k^2 r_{original}^2 = k^2 \cdot A_{original}$.
In this problem, the radius is decreased by 11%, so the new radius is $100\% - 11\% = 89\%$ of the original radius. This means the factor $k = 0.89$.
The new area is $A_{new} = (0.89)^2 A_{original} = 0.7921 A_{original}$.
This means the new area is 79.21% of the original area. The decrease in area is $100\% - 79.21\% = 20.79\%$ of the original area.
A common mistake is to assume the area decrease is just twice the radius decrease (i.e., $2 \times 11\% = 22\%$), but this is an approximation only valid for very small percentage changes. The actual calculation involving squaring the factor is necessary for accuracy.
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