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Question

The Cartesian coordinates (x, y) of a point A with polar coordinates $(4, \frac{\pi}{4})$ is

The correct answer is
$(2\sqrt{2}, 2\sqrt{2})$

Polar to Cartesian Conversion

The question asks for the Cartesian coordinates $(x, y)$ corresponding to the polar coordinates $(r, \theta) = (4, \frac{\pi}{4})$.

The conversion formulas from polar coordinates $(r, \theta)$ to Cartesian coordinates $(x, y)$ are:

  • $x = r \cos(\theta)$
  • $y = r \sin(\theta)$

Calculating Cartesian Coordinates

Substitute the given values $r = 4$ and $\theta = \frac{\pi}{4}$ into the formulas:

  • Calculate x-coordinate:

    $x = 4 \cos(\frac{\pi}{4})$
    Since $\cos(\frac{\pi}{4}) = \frac{\sqrt{2}}{2}$,
    $x = 4 \times \frac{\sqrt{2}}{2}$
    $x = 2\sqrt{2}$

  • Calculate y-coordinate:

    $y = 4 \sin(\frac{\pi}{4})$
    Since $\sin(\frac{\pi}{4}) = \frac{\sqrt{2}}{2}$,
    $y = 4 \times \frac{\sqrt{2}}{2}$
    $y = 2\sqrt{2}$

Therefore, the Cartesian coordinates are $(2\sqrt{2}, 2\sqrt{2})$.

Final Answer Check

Comparing the calculated coordinates $(2\sqrt{2}, 2\sqrt{2})$ with the given options, Option D matches the result.

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Important Questions from Calculus

  1. f(x) = 2x2 – 1, then f(0) = _______.
  2. Find the value of integral I = \(\smallint \frac{1}{{x + \sqrt x }}\)dx. (where c = constant)

  3. Differentiate (a cos 3t) w.r.t. to (a sin 3t)

  4. Find the slope of normal to the curve y = x2 + 7x at (1, 8).

  5. Find the equation of normal to the curve y = 4x - 3x2 at (2, -4).

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