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Question

f(x) = 2x2 – 1, then f(0) = _______.

The correct answer is

-1

Evaluating the Function f(x) = 2x2 – 1

The question asks us to find the value of the function f(x) = 2x2 – 1 when x is equal to 0. This is denoted as finding f(0).

To find f(0), we need to substitute every occurrence of 'x' in the function definition with the value '0'.

Step-by-Step Calculation for f(0)

  1. Start with the given function:
    \(f(x) = 2x^2 - 1\)
  2. Substitute x = 0 into the function:
    \(f(0) = 2(0)^2 - 1\)
  3. First, evaluate the term with the power: \(0^2 = 0\).
    \(f(0) = 2(0) - 1\)
  4. Next, perform the multiplication: \(2 \times 0 = 0\).
    \(f(0) = 0 - 1\)
  5. Finally, perform the subtraction: \(0 - 1 = -1\).
    \(f(0) = -1\)

So, the value of the function f(x) at x = 0 is -1.

Comparing this result with the given options:

  • Option 1: 1
  • Option 2: -1
  • Option 3: 0
  • Option 4: None of the above

Our calculated value f(0) = -1 matches Option 2.

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Important Questions from Calculus

  1. Find the value of integral I = \(\smallint \frac{1}{{x + \sqrt x }}\)dx. (where c = constant)

  2. Differentiate (a cos 3t) w.r.t. to (a sin 3t)

  3. Find the slope of normal to the curve y = x2 + 7x at (1, 8).

  4. Find the equation of normal to the curve y = 4x - 3x2 at (2, -4).

  5. The value of \(\int^2_0\int^x_0y\ dy\ dx\)

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