The average of 24 numbers is 43. If we subtract a number 'M' from each number, then the average becomes 38. What was the value of M?
5
This problem involves calculating the value of a number 'M' that is subtracted from each number in a set, resulting in a change in the average of the set.
The average of a set of numbers is calculated by summing all the numbers and dividing by the count of numbers.
\text{Average} = \frac{\text{Sum of Numbers}}{\text{Number of Numbers}}
A key property of averages states that if a constant value is added to or subtracted from every number in a set, the average of the new set will be the original average plus or minus that constant value, respectively.
In this case, 'M' is subtracted from each number. Therefore, the new average is equal to the original average minus 'M'.
\text{New Average} = \text{Original Average} - \text{M}
We are given the original average (43) and the new average (38). We can substitute these values into the equation:
$$38 = 43 - M$$
Now, we need to solve for M. We can rearrange the equation to isolate M:
$$M = 43 - 38$$
Performing the subtraction:
$$M = 5$$
So, the value of M is 5.
We can also solve this by calculating the sum of the numbers.
Step 1: Calculate the initial sum.
Using the formula: Sum = Average \(\times\) Number of Numbers
$$ \text{Initial Sum} = 43 \times 24 $$
$$ \text{Initial Sum} = 1032 $$
Step 2: Calculate the new sum.
The new average is 38, and there are still 24 numbers.
$$ \text{New Sum} = 38 \times 24 $$
$$ \text{New Sum} = 912 $$
Step 3: Relate the sums to M.
When M is subtracted from each of the 24 numbers, the total sum decreases by \(24 \times M\).
$$ \text{New Sum} = \text{Initial Sum} - (24 \times M) $$
Substitute the calculated sums:
$$ 912 = 1032 - (24 \times M) $$
Rearrange the equation to solve for \(24 \times M\):
$$ 24 \times M = 1032 - 912 $$
$$ 24 \times M = 120 $$
Now, solve for M:
$$ M = \frac{120}{24} $$
$$ M = 5 $$
Both methods confirm that the value of M is 5.
| Concept | Description | Formula/Property |
|---|---|---|
| Average (Mean) | The sum of all values divided by the number of values. | \( \text{Average} = \frac{\sum x}{n} \) |
| Effect of Adding/Subtracting a Constant | If a constant 'k' is added to (or subtracted from) each value, the new average is the old average plus (or minus) 'k'. | \( \text{New Avg} = \text{Old Avg} \pm k \) |
| Effect of Multiplying/Dividing by a Constant | If each value is multiplied (or divided) by a constant 'k' (k \(\neq\) 0), the new average is the old average multiplied (or divided) by 'k'. | \( \text{New Avg} = \text{Old Avg} \times k \) \( \text{New Avg} = \frac{\text{Old Avg}}{k} \) |
Understanding how operations on individual data points affect summary statistics like the average is crucial in data analysis and statistics.
This problem specifically used the property related to subtracting a constant, which simplifies the calculation significantly.
| Marks obtained | No. of students |
| 25 | 5 |
| 30 | 6 |
| 35 | 3 |
| 40 | 1 |
The average runs scored by a batsman in 23 matches is 40. In the next 10 matches, the batsman scored an average of 16 runs. Find his average runs scored (rounded off to two decimals) in all the 33 matches.