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Question

The following table shows the number of students (Boys and Girls) and the percentage of girls who passed in a 10+2 examination from six different schools (A-F) in the year 2023 and 2024. Based on the data in the table, answer the questions that follow.
School-wise Details of Students Passing in a 10+2 examination
 

SchoolYear
Year 2023Year 2024
Number of Passed StudentsPercentage of Passed GirlsNumber of Passed StudentsPercentage of Passed Girls
A50046%55044%
B60042%64040%
C65056%56045%
D72060%80048%
E60054%84055%
F65050%75036%

The average number of girls who passed in the year 2024 from all the six schools is ________% of the number of students who passed from School A in the year 2023.

The correct answer is
62.2

Analyzing 10+2 Exam Data: Girls Passing Percentage

This problem requires us to compare the performance of students across different schools based on the provided data table. We need to find the average number of girls who passed the 10+2 examination in the year 2024 across all six schools (A-F). Then, we must express this average as a percentage of the total number of students who passed from School A in the year 2023.

Step 1: Calculate the Number of Girls Passed in 2024 for Each School

First, let's calculate the number of girls who passed from each school in 2024 using the total passed students and the percentage of girls passed.

  • School A (2024): Total Passed = 550, Percentage of Girls Passed = 44%
    Number of Girls = $550 \times \frac{44}{100} = 550 \times 0.44 = 242$
  • School B (2024): Total Passed = 640, Percentage of Girls Passed = 40%
    Number of Girls = $640 \times \frac{40}{100} = 640 \times 0.40 = 256$
  • School C (2024): Total Passed = 560, Percentage of Girls Passed = 45%
    Number of Girls = $560 \times \frac{45}{100} = 560 \times 0.45 = 252$
  • School D (2024): Total Passed = 800, Percentage of Girls Passed = 48%
    Number of Girls = $800 \times \frac{48}{100} = 800 \times 0.48 = 384$
  • School E (2024): Total Passed = 840, Percentage of Girls Passed = 55%
    Number of Girls = $840 \times \frac{55}{100} = 840 \times 0.55 = 462$
  • School F (2024): Total Passed = 750, Percentage of Girls Passed = 36%
    Number of Girls = $750 \times \frac{36}{100} = 750 \times 0.36 = 270$

Step 2: Calculate the Total Number of Girls Passed in 2024

Sum the number of girls passed from all six schools in 2024:

Total Girls Passed (2024) = $242 + 256 + 252 + 384 + 462 + 270 = 1866$

Step 3: Calculate the Average Number of Girls Passed in 2024

Find the average by dividing the total number of girls passed by the number of schools (which is 6):

Average Girls Passed (2024) = $\frac{\text{Total Girls Passed (2024)}}{\text{Number of Schools}}$

Average Girls Passed (2024) = $\frac{1866}{6} = 311$

Step 4: Identify the Number of Students Passed from School A in 2023

From the table, the number of students who passed from School A in the year 2023 is 500.

Step 5: Calculate the Required Percentage

Now, we need to find what percentage the average number of girls passed in 2024 (311) is of the number of students passed from School A in 2023 (500):

Percentage = $\left( \frac{\text{Average Girls Passed (2024)}}{\text{School A Passed Students (2023)}} \right) \times 100$

Percentage = $\left( \frac{311}{500} \right) \times 100$

Percentage = $\frac{311}{5}$

Percentage = $62.2\%$

Therefore, the average number of girls who passed in the year 2024 from all the six schools is 62.2% of the number of students who passed from School A in the year 2023.

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Important Questions from Average

  1. Find the mean marks of the following distribution.
    Marks obtainedNo. of students
    255
    306
    353
    401
  2. The average of first 169 even numbers is
  3. The average weight (in kg) of a family of five members whose weights are 40 kg, 49 kg, 56 kg, 74 kg and 35 kg is:
  4. The average of first 152 odd natural numbers, is:
  5. The average runs scored by a batsman in 23 matches is 40. In the next 10 matches, the batsman scored an average of 16 runs. Find his average runs scored (rounded off to two decimals) in all the 33 matches.

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