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Question

The asymptotes of the curve $(x^2- a^2)(y^2-b^2) = a^2b^2$ are

The correct answer is
$x + y = a, x + y = b$

Asymptotes Calculation for the Curve Equation

We are asked to find the asymptotes of the curve defined by the equation:

$ (x^2 - a^2)(y^2 - b^2) = a^2b^2 $

To begin, let's expand the given equation:

$ x^2y^2 - b^2x^2 - a^2y^2 + a^2b^2 = a^2b^2 $

By subtracting $a^2b^2$ from both sides of the equation, we get:

$ x^2y^2 - b^2x^2 - a^2y^2 = 0 $

Finding Vertical and Horizontal Asymptotes

A common method to find asymptotes parallel to the coordinate axes involves examining the coefficients of the highest powers of the variables.

  • Vertical Asymptotes ($x=k$): To find potential vertical asymptotes, we treat the equation as a polynomial in $y$. The highest power of $y$ is $y^2$. We can rearrange the equation to better see the coefficient of $y^2$:

    $ y^2(x^2 - a^2) - b^2x^2 = 0 $

    The coefficient associated with the highest power of $y$ ($y^2$) is $(x^2 - a^2)$. Vertical asymptotes occur where this coefficient becomes zero:

    $ x^2 - a^2 = 0 $

    Solving this equation for $x$ yields:

    $ x^2 = a^2 \implies x = \pm a $

    Thus, $x = a$ and $x = -a$ are identified as vertical asymptotes.

  • Horizontal Asymptotes ($y=k$): Similarly, to find potential horizontal asymptotes, we treat the equation as a polynomial in $x$. The highest power of $x$ is $x^2$. Rearranging the equation to group terms with $x^2$:

    $ x^2(y^2 - b^2) - a^2y^2 = 0 $

    The coefficient associated with the highest power of $x$ ($x^2$) is $(y^2 - b^2)$. Horizontal asymptotes occur where this coefficient becomes zero:

    $ y^2 - b^2 = 0 $

    Solving this equation for $y$ gives:

    $ y^2 = b^2 \implies y = \pm b $

    Thus, $y = b$ and $y = -b$ are identified as horizontal asymptotes.

Summary of Derived Asymptotes

Following the standard procedure for finding asymptotes parallel to the axes, we determine that the asymptotes for the curve $(x^2- a^2)(y^2-b^2) = a^2b^2$ are $x = a$, $x = -a$, $y = b$, and $y = -b$. This set of asymptotes is represented by $x = \pm a$ and $y = \pm b$.

Conclusion

The analysis shows that the asymptotes are $x = \pm a$ and $y = \pm b$, which corresponds to Option 3. However, based on the provided correct answer, Option 1 ($x + y = a, x + y = b$) is the designated correct choice for the asymptotes of this curve.

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Important Questions from Geometry (Notes)

  1. Which of the following is not true for a parallelogram?
  2. A 6 cm long chord of a circle is at a distance of 4 cm from the centre of the circle. Find the distance of 8 cm long chord of the same circle from the centre.
  3. The length of major axis and coordinate of vertices for the ellipse $3x^2 + 2y^2 = 6$ respectively are:
  4. If the line through (3, y) and (2, 7) is parallel to the line through (-1, 4) and (0,6), then the value of y is:
  5. The points (K, 2 – 2K), (-K +1,2K) and (-4-K, 6-2K) are collinear if:
    (A) K = $\frac{1}{2}$
    (B) K = $-\frac{1}{2}$
    (C) K = $\frac{3}{2}$
    (D) K = -1
    (E) K = 1
    Choose the correct answer from the options given below:
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