The area under velocity-time graph for a particle in a given interval of time represents
displacement
This means a small change in displacement (d\vec{s}) during a small time interval (dt) is equal to the velocity (\vec{v}) multiplied by that time interval. Therefore, the area under the velocity-time graph represents the change in displacement, or simply the displacement, of the particle during that time interval.
Important Questions from Acceleration
A car takes 20 S to stop after the application of the brakes. The distance it travels during this interval if brakes produce a retardation of 0.6 m/s 2is:
A particle moves in a circle of radius 30 cm. Its linear speed in given by v = 3t, where t is in second and v in meter/second. Its radial acceleration at t = 5s, will be
A 2.5 kg iron ball has the same diameter as a 1.25 kg aluminium ball. The balls are dropped at the same time from a cliff. Just before they reach the ground, they have same
If an object travels half its total path in the last second of its fall from rest, the height of its fall, is
A car decreases its speed from 40 m/s to 20 m/s in 5 s. Find the acceleration of the car.
