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Question

The area of a square is double the area of rectangle. The perimeter of the square is 56 m. if length of the rectangle is double that of the breadth find the perimeter of the rectangle.

This question was previously asked in
ESIC UDC Mains MBT (30 Apr 2022)
The correct answer is

42 m

This problem involves calculating the perimeter of a rectangle based on its relationship with a square's area and perimeter. Let's break it down step-by-step.

Finding the Square's Dimensions

We are given that the perimeter of the square is 56 m. The formula for the perimeter of a square is:

$$ \text{Perimeter}_{\text{square}} = 4 \times \text{side} $$

Using the given information:

$$ 56 \text{ m} = 4 \times \text{side} $$

To find the length of one side of the square, we divide the perimeter by 4:

$$ \text{side} = \frac{56 \text{ m}}{4} = 14 \text{ m} $$

Calculating the Square's Area

Now that we have the side length of the square, we can calculate its area. The formula for the area of a square is:

$$ \text{Area}_{\text{square}} = \text{side}^2 $$

Substituting the side length we found:

$$ \text{Area}_{\text{square}} = (14 \text{ m})^2 = 196 \text{ m}^2 $$

Determining the Rectangle's Area

The problem states that the area of the square is double the area of the rectangle. So:

$$ \text{Area}_{\text{square}} = 2 \times \text{Area}_{\text{rectangle}} $$

We can rearrange this to find the rectangle's area:

$$ \text{Area}_{\text{rectangle}} = \frac{\text{Area}_{\text{square}}}{2} $$

Plugging in the square's area:

$$ \text{Area}_{\text{rectangle}} = \frac{196 \text{ m}^2}{2} = 98 \text{ m}^2 $$

Finding the Rectangle's Dimensions

Let the breadth of the rectangle be '$b$' and the length be '$l$'. We are given that the length of the rectangle is double its breadth:

$$ l = 2b $$

The formula for the area of a rectangle is:

$$ \text{Area}_{\text{rectangle}} = l \times b $$

Substitute '$l = 2b$' into the area formula:

$$ \text{Area}_{\text{rectangle}} = (2b) \times b = 2b^2 $$

We know the area of the rectangle is 98 m², so:

$$ 98 \text{ m}^2 = 2b^2 $$

Now, solve for '$b^2$':

$$ b^2 = \frac{98 \text{ m}^2}{2} = 49 \text{ m}^2 $$

Take the square root to find the breadth '$b$':

$$ b = \sqrt{49 \text{ m}^2} = 7 \text{ m} $$

Now find the length '$l$' using the relation $l = 2b$:

$$ l = 2 \times 7 \text{ m} = 14 \text{ m} $$

Calculating the Rectangle's Perimeter

Finally, we calculate the perimeter of the rectangle using its length and breadth. The formula for the perimeter of a rectangle is:

$$ \text{Perimeter}_{\text{rectangle}} = 2(l + b) $$

Substitute the values of '$l$' and '$b$':

$$ \text{Perimeter}_{\text{rectangle}} = 2(14 \text{ m} + 7 \text{ m}) $$

$$ \text{Perimeter}_{\text{rectangle}} = 2(21 \text{ m}) $$

$$ \text{Perimeter}_{\text{rectangle}} = 42 \text{ m} $$

Conclusion

Therefore, the perimeter of the rectangle is 42 m.

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Similar Questions

  1. The perimeter of a square with diagonal 29√2 cm is equal to the perimeter of a rectangle. Find the area of the rectangle if the length of the rectangle is 8 cm more than the breadth of the rectangle?


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  5. What is the perpendicular distance (in cm) between the parallel sides of a trapezium whose area is 108 sqcm. and the lengths of the parallel sides are 9 cm and 36 cm?

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