The area of a square is double the area of rectangle. The perimeter of the square is 56 m. if length of the rectangle is double that of the breadth find the perimeter of the rectangle.
42 m
This problem involves calculating the perimeter of a rectangle based on its relationship with a square's area and perimeter. Let's break it down step-by-step.
We are given that the perimeter of the square is 56 m. The formula for the perimeter of a square is:
$$ \text{Perimeter}_{\text{square}} = 4 \times \text{side} $$
Using the given information:
$$ 56 \text{ m} = 4 \times \text{side} $$
To find the length of one side of the square, we divide the perimeter by 4:
$$ \text{side} = \frac{56 \text{ m}}{4} = 14 \text{ m} $$
Now that we have the side length of the square, we can calculate its area. The formula for the area of a square is:
$$ \text{Area}_{\text{square}} = \text{side}^2 $$
Substituting the side length we found:
$$ \text{Area}_{\text{square}} = (14 \text{ m})^2 = 196 \text{ m}^2 $$
The problem states that the area of the square is double the area of the rectangle. So:
$$ \text{Area}_{\text{square}} = 2 \times \text{Area}_{\text{rectangle}} $$
We can rearrange this to find the rectangle's area:
$$ \text{Area}_{\text{rectangle}} = \frac{\text{Area}_{\text{square}}}{2} $$
Plugging in the square's area:
$$ \text{Area}_{\text{rectangle}} = \frac{196 \text{ m}^2}{2} = 98 \text{ m}^2 $$
Let the breadth of the rectangle be '$b$' and the length be '$l$'. We are given that the length of the rectangle is double its breadth:
$$ l = 2b $$
The formula for the area of a rectangle is:
$$ \text{Area}_{\text{rectangle}} = l \times b $$
Substitute '$l = 2b$' into the area formula:
$$ \text{Area}_{\text{rectangle}} = (2b) \times b = 2b^2 $$
We know the area of the rectangle is 98 m², so:
$$ 98 \text{ m}^2 = 2b^2 $$
Now, solve for '$b^2$':
$$ b^2 = \frac{98 \text{ m}^2}{2} = 49 \text{ m}^2 $$
Take the square root to find the breadth '$b$':
$$ b = \sqrt{49 \text{ m}^2} = 7 \text{ m} $$
Now find the length '$l$' using the relation $l = 2b$:
$$ l = 2 \times 7 \text{ m} = 14 \text{ m} $$
Finally, we calculate the perimeter of the rectangle using its length and breadth. The formula for the perimeter of a rectangle is:
$$ \text{Perimeter}_{\text{rectangle}} = 2(l + b) $$
Substitute the values of '$l$' and '$b$':
$$ \text{Perimeter}_{\text{rectangle}} = 2(14 \text{ m} + 7 \text{ m}) $$
$$ \text{Perimeter}_{\text{rectangle}} = 2(21 \text{ m}) $$
$$ \text{Perimeter}_{\text{rectangle}} = 42 \text{ m} $$
Therefore, the perimeter of the rectangle is 42 m.
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