This problem involves finding the area of a regular hexagon when we know the area of a square and that their perimeters are equal. Let's break down the steps:
We are given the area of the square:
Area$_{square}$ = $324 \, \text{cm}^2$
The formula for the area of a square with side length '$s$' is:
Area$_{square}$ = $s^2$
To find the side length '$s$', we take the square root of the area:
$s = \sqrt{\text{Area}_{square}}$
$s = \sqrt{324 \, \text{cm}^2}$
$s = 18 \, \text{cm}$
Now, we find the perimeter of the square. The formula for the perimeter of a square with side length '$s$' is:
Perimeter$_{square}$ = $4s$
Perimeter$_{square}$ = $4 \times 18 \, \text{cm}$
Perimeter$_{square}$ = $72 \, \text{cm}$
The problem states that the perimeter of the square is equal to the perimeter of a regular hexagon.
Perimeter$_{hexagon}$ = Perimeter$_{square}$
Perimeter$_{hexagon}$ = $72 \, \text{cm}$
A regular hexagon has 6 equal sides. Let the side length of the hexagon be '$h$'. The formula for the perimeter of a regular hexagon is:
Perimeter$_{hexagon}$ = $6h$
We can now find the side length '$h$' of the hexagon:
$6h = 72 \, \text{cm}$
$h = \frac{72 \, \text{cm}}{6}$
$h = 12 \, \text{cm}$
The formula for the area of a regular hexagon with side length '$h$' is:
Area$_{hexagon}$ = $\frac{3\sqrt{3}}{2} h^2$
Substitute the value of '$h$' we found:
Area$_{hexagon}$ = $\frac{3\sqrt{3}}{2} (12 \, \text{cm})^2$
Area$_{hexagon}$ = $\frac{3\sqrt{3}}{2} \times 144 \, \text{cm}^2$
Area$_{hexagon}$ = $3\sqrt{3} \times \frac{144}{2} \, \text{cm}^2$
Area$_{hexagon}$ = $3\sqrt{3} \times 72 \, \text{cm}^2$
Area$_{hexagon}$ = $216\sqrt{3} \, \text{cm}^2$
The area of the regular hexagon is $216\sqrt{3} \, \text{cm}^2$. This corresponds to the second option.
The difference between two parallel sides of a trapezium is 9 cm. The perpendicular distance between them is 52 cm. If the area of the trapezium is 988 \(cm^2\), find the lengths of the parallel sides (in cm).