We are asked to find the perimeter of a rhombus. We are provided with two key pieces of information about this rhombus:
To find the perimeter, we first need to determine the length of one side of the rhombus, as all sides of a rhombus are equal.
The area of a rhombus can be calculated using its side length and one of its interior angles. The formula is:
$Area = s^2 \sin(\theta)$
In this formula:
Let's substitute the given values into the area formula:
So, the equation becomes:
$10 = s^2 \sin(150^{\circ})$
We need to find the value of $\sin(150^{\circ})$. We can use the property that $\sin(180^{\circ} - x) = \sin(x)$.
Therefore:
$\sin(150^{\circ}) = \sin(180^{\circ} - 30^{\circ}) = \sin(30^{\circ})$
The value of $\sin(30^{\circ})$ is a standard trigonometric value:
$\sin(30^{\circ}) = \frac{1}{2}$
So, $\sin(150^{\circ}) = \frac{1}{2}$.
Now, substitute the value of $\sin(150^{\circ})$ back into our area equation:
$10 = s^2 \times \frac{1}{2}$
To find $s^2$, we multiply both sides of the equation by 2:
$10 \times 2 = s^2$
$20 = s^2$
To find the side length 's', we take the square root of both sides:
$s = \sqrt{20}$
We can simplify $\sqrt{20}$ by finding perfect square factors:
$s = \sqrt{4 \times 5} = \sqrt{4} \times \sqrt{5} = 2\sqrt{5}$
The length of one side of the rhombus is $2\sqrt{5}$ cm.
The perimeter of a rhombus is calculated by multiplying the side length by 4, since all four sides are equal.
$Perimeter = 4 \times s$
Using the side length we found:
Perimeter = $4 \times (2\sqrt{5})$
Perimeter = $8\sqrt{5}$ cm
The perimeter of the rhombus is $8\sqrt{5}$ cm.