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Question

If the area of a rhombus is $10\text{ cm}^2$ and one of its interior angles is $150^{\circ}$, what is the perimeter (in cm) of the rhombus?

The correct answer is
$8\sqrt{5}$

Calculating the Rhombus Perimeter from Area and Angle

Understanding the Given Information

We are asked to find the perimeter of a rhombus. We are provided with two key pieces of information about this rhombus:

  • The area of the rhombus is $10\text{ cm}^2$.
  • One of its interior angles is $150^{\circ}$.

To find the perimeter, we first need to determine the length of one side of the rhombus, as all sides of a rhombus are equal.

Rhombus Area Formula Explained

The area of a rhombus can be calculated using its side length and one of its interior angles. The formula is:

$Area = s^2 \sin(\theta)$

In this formula:

  • $s$ represents the length of a side of the rhombus.
  • $\theta$ represents one of the interior angles of the rhombus.

Step 1: Applying the Area Formula

Let's substitute the given values into the area formula:

  • Area = $10\text{ cm}^2$
  • \theta = $150^{\circ}$

So, the equation becomes:

$10 = s^2 \sin(150^{\circ})$

Step 2: Determining the Sine of the Angle

We need to find the value of $\sin(150^{\circ})$. We can use the property that $\sin(180^{\circ} - x) = \sin(x)$.

Therefore:

$\sin(150^{\circ}) = \sin(180^{\circ} - 30^{\circ}) = \sin(30^{\circ})$

The value of $\sin(30^{\circ})$ is a standard trigonometric value:

$\sin(30^{\circ}) = \frac{1}{2}$

So, $\sin(150^{\circ}) = \frac{1}{2}$.

Step 3: Calculating the Side Length (s)

Now, substitute the value of $\sin(150^{\circ})$ back into our area equation:

$10 = s^2 \times \frac{1}{2}$

To find $s^2$, we multiply both sides of the equation by 2:

$10 \times 2 = s^2$

$20 = s^2$

To find the side length 's', we take the square root of both sides:

$s = \sqrt{20}$

We can simplify $\sqrt{20}$ by finding perfect square factors:

$s = \sqrt{4 \times 5} = \sqrt{4} \times \sqrt{5} = 2\sqrt{5}$

The length of one side of the rhombus is $2\sqrt{5}$ cm.

Step 4: Calculating the Perimeter

The perimeter of a rhombus is calculated by multiplying the side length by 4, since all four sides are equal.

$Perimeter = 4 \times s$

Using the side length we found:

Perimeter = $4 \times (2\sqrt{5})$

Perimeter = $8\sqrt{5}$ cm

Final Answer

The perimeter of the rhombus is $8\sqrt{5}$ cm.

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Important Questions from Mensuration 2D (Notes)

  1. Find the area of a quadrilateral ABCD whose area is twice the area of a triangle PQR. The sides of triangle PQR are in the ratio 4:5:6 and the perimeter of the triangle is 90 cm (use $\sqrt{7} = 2.6$).
  2. Find the area of a regular hexagon whose side measures $14\sqrt{3}$ cm.
  3. Find the perimeter of the semi-circle of radius 21 cm.
    $\left(\text{Take } \pi = \frac{22}{7}\right)$
  4. The length of a diagonal of a rectangular park is 25 meters, and that of one of its sides is 15 meters. Find the perimeter of the park.
  5. If the area of an equilateral triangle is given as $900 \text{ m}^2$, then what is its perimeter?
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