The ages of Misha and Kamal are in the ratio of 4 : 3 respectively. After 9 years the ratio of their ages will be 7 : 6. What is the difference in their present ages?
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Let the present ages of Misha and Kamal be 4x and 3x respectively. After 9 years, the ages will be (4x + 9) and (3x + 9). According to the given condition:
(4x + 9) / (3x + 9) = 7/6
Cross-multiply: 6(4x + 9) = 7(3x + 9)
24x + 54 = 21x + 63
24x - 21x = 63 - 54
3x = 9
x = 3
Present ages are 4x = 12 and 3x = 9, so the difference in their present ages = 12 - 9 = 3 years.
Important Questions from Age
The ratio of the ages of A and B, four years ago, was 4 : 5. Eight years from now, the ratio of the ages of A and B will be 11 : 13. What is the sum of their present ages?
The ratio of the present ages of A and B is 8 : 9. After 9 years, this ratio will become 19 : 21. C is 3 years younger to B. What is the present (in years) of C?
The ratio of the ages of A and B 8 years ago was 2 : 3. Four years ago, the ratio of their ages was 5 : 7. What will be the ratio of their ages 8 years from now?
The ratio of the present age of father to that of his son is 7 : 2. If after 10 years the ratio of their ages will become 9 : 4, then the present age of the father is:
The ages of two persons P and Q are in the ratio 5 : 7. Eight years ago, the ratio of P and Q was 7 : 13. The present ages of P and Q, respectively, are:
