The ages of Misha and Kamal are in the ratio of 4 : 3 respectively. After 9 years the ratio of their ages will be 7 : 6. What is the difference in their present ages?
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Let the present ages of Misha and Kamal be 4x and 3x respectively. After 9 years, the ages will be (4x + 9) and (3x + 9). According to the given condition:
(4x + 9) / (3x + 9) = 7/6
Cross-multiply: 6(4x + 9) = 7(3x + 9)
24x + 54 = 21x + 63
24x - 21x = 63 - 54
3x = 9
x = 3
Present ages are 4x = 12 and 3x = 9, so the difference in their present ages = 12 - 9 = 3 years.
Important Questions from Age
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If 2 times the mother's age is 26 years more than 4 times her daughter's age, and 3 times the daughter's age is 7 years less than the mother's age, then what is the difference (in years) between the ages of the mother and the daughter?
If 2 times a son's age is added to his father's age, the sum is 36 years. If 2.5 times the father's age is added to the son's age, the sum is 72 years. What is the father's age (in years)?
- Six times the present age of P exceeds the present age of Q by 11 years. After 10 years, three times Q's age will be 27 years less than six times P's age at that time. What is the present age (in years) of Q?
