The ages of Misha and Kamal are in the ratio of 4 : 3 respectively. After 9 years the ratio of their ages will be 7 : 6. What is the difference in their present ages?
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Let the present ages of Misha and Kamal be 4x and 3x respectively. After 9 years, the ages will be (4x + 9) and (3x + 9). According to the given condition:
(4x + 9) / (3x + 9) = 7/6
Cross-multiply: 6(4x + 9) = 7(3x + 9)
24x + 54 = 21x + 63
24x - 21x = 63 - 54
3x = 9
x = 3
Present ages are 4x = 12 and 3x = 9, so the difference in their present ages = 12 - 9 = 3 years.
Important Questions from Age
The ages of two persons P and Q are in the ratio 5 : 7. Eight years ago, the ratio of P and Q was 7 : 13. The present ages of P and Q, respectively, are:
One year ago, the ratio of the ages of A and B was 4 : 3. The ratio of their ages, after 7 years from now, will be 9 : 7. What is the present age (in years) of B?
In 8 years, Subhash will be 3 times as old as he is now. After how many years will Subhash be 5 times as old as he is now?
The average ages of parents and two children are 30 years and 8 years respectively. The average age of the family is
A. 16 years
B. 19 years
C. 18 years
D. 17 years
A father is presently 3 times his daughter’s age. After 10 years he will be twice as old as her. Find the daughter’s present age.
