This problem involves calculating the total cost of a gift based on a shared contribution that changes when some contributors withdraw.
Ten friends initially planned to share the cost of a gift equally. Let the total cost of the gift be denoted by $C$.
The initial number of friends is 10.
The share per friend initially would be: $ \text{Initial Share} = \frac{C}{10} $
Two friends decided not to contribute. This leaves $10 - 2 = 8$ friends to share the cost.
The new share per contributing friend is: $ \text{New Share} = \frac{C}{8} $
Each of the remaining friends had to pay Rs 150 more than their initial planned share. This gives us the equation:
$ \text{New Share} - \text{Initial Share} = 150 $Substituting the expressions for the shares:
$ \frac{C}{8} - \frac{C}{10} = 150 $To solve for $C$, we first find a common denominator for 8 and 10, which is 40.
Therefore, the total cost of the gift was Rs 6000.
Three frictionless pulleys with rope attachment are in a static equilibrium as shown in the figure. The mass $m_1$ and $m_2$, in kg, respectively are

If the in-situ density of coal is 1320 kg/m$^3$ and the density of blasted coal is 952 kg/m$^3$, the swell factor is _____________ (rounded off to 3 decimal places)
A five-member truss system is shown in the figure. The maximum vertical force P in kN that can be applied so that loads on the member CD and BC do NOT exceed 50 kN and 30 kN, respectively is _____________(rounded off to 2 decimal places)
The Fourier transform and its inverse transform are respectively defined as $\tilde{f}(\omega) = \frac{1}{\sqrt{2\pi}} \int_{-\infty}^{+\infty} f(x)e^{i\omega x}dx$ and $f(x) = \frac{1}{\sqrt{2\pi}} \int_{-\infty}^{+\infty} \tilde{f}(\omega)e^{-i\omega x}d\omega$. Consider two functions $f$ and $g$. Another function $f * g$ is defined as
$(f * g)(x) = \frac{1}{\sqrt{2\pi}} \int_{-\infty}^{+\infty} f(y)g(x - y)dy$
Which of the following relation is/are true?
Note: Tilde ($\sim$) denotes the Fourier transform.