Suppose $X$ and $Y$ are independent and identically distributed random variables that are distributed uniformly in the interval $[0,1]$. The probability that $X \ge Y$ is _________
We are given two random variables, X and Y, which are independent and identically distributed (i.i.d.). Both follow a uniform distribution on the interval $[0, 1]$, denoted as X, Y ~ U[0, 1]. We need to find the probability P(X ≥ Y).
The joint distribution of X and Y is uniform over the unit square defined by $0 \le x \le 1$ and $0 \le y \le 1$. The total area of this sample space is $1 \times 1 = 1$.
The condition X ≥ Y corresponds to the region within the unit square where the x-coordinate is greater than or equal to the y-coordinate. This region is a triangle with vertices at (0, 0), (1, 0), and (1, 1).
The area of this favorable region (the triangle) is calculated as:
Area = $\frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 1 \times 1 = \frac{1}{2}$.
Since the joint distribution is uniform, the probability of the event X ≥ Y is the ratio of the favorable area to the total area of the sample space:
P(X ≥ Y) = $\frac{\text{Area where } X \ge Y}{\text{Total Area}} = \frac{1/2}{1} = \frac{1}{2}$.
Alternatively, due to symmetry (since X and Y are i.i.d. from the same distribution), the probability P(X > Y) must be equal to P(Y > X). Since P(X=Y) = 0 for continuous distributions, we have P(X ≥ Y) = P(X > Y). Also, P(X > Y) + P(Y > X) + P(X=Y) = 1. This simplifies to 2 * P(X > Y) = 1, so P(X > Y) = 1/2. Therefore, P(X ≥ Y) = 1/2.
Suppose a 5-bit message is transmitted from a source to a destination through a noisy channel. The probability that a bit of the message gets flipped during transmission is 0.01. Flipping of each bit is independent of one another. The probability that the message is delivered error-free to the destination is ______ . (rounded off to three decimal places)
For a distribution with mean, median, mode and standard deviation 25, 24, 26 and 5 respectively, Karl Pearson's coefficient of skewness equals to:
Suppose two distributions have the same mean, same standard deviation and are equally skewed, but the first distribution is more peaked than the
other. This feature of the frequency distributions in which they are different are called: