Suppose 1 ≤ x, y, z ≤ 9 are integers such that x > z. Let α and β be the three-digit numbers given by α = xyz and β = zyx so that x, y, z are the digits as they are shown. Set γ = α − β. How many of the following statements are always true? Select the correct answer.
3
To solve the problem, we need to analyze each statement by calculating the difference \(\gamma = \alpha - \beta\) where:
\(\alpha = 100x + 10y + z\)
\(\beta = 100z + 10y + x\)
To find \(\gamma\), compute:
<[\( \gamma = (100x + 10y + z) - (100z + 10y + x) = 99x - 99z = 99(x - z) \)\]
Since \(\gamma = 99(x - z)\) where \(x > z\) and 1 ≤ \(x, y, z ≤ 9\), let's analyze each statement:
Based on the analysis above, the statements that are always true are 2, 3, and 5. Hence, the number of statements that are always true is:
The correct option is 3 as only three statements are always true.
Consider the following statements :
1. (25)! + 1 is divisible by 26
2. (6)! + 1 is divisible by 7
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