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Question

Direction: Study the information given carefully and answer the question given below.

‘A # B’ means ‘A is either smaller than or equal to B.’
‘A $ B’ means ‘A is neither smaller than nor equal to B.’
‘A + B’ means ‘A is either greater than or equal to B.’
‘A @ B’ means ‘A is neither greater than nor equal to B.’
‘A * B’ means ‘A is neither greater than nor smaller than B.’

Statement: S @ T $ Q + R; Q * P @ W

Conclusion:

I)  R # W

II)  W $ R

III) R @ T

The correct answer is Only II and III follow

Let's first decode the given symbols into standard mathematical inequalities:

  • 'A # B' means 'A ≤ B'
  • 'A $ B' means 'A > B'
  • 'A + B' means 'A ≥ B'
  • 'A @ B' means 'A < B'
  • 'A * B' means 'A = B'

Now, let's translate the given statement into inequalities:

Statement: S @ T $ Q + R; Q * P @ W

  • S @ T translates to S < T
  • T $ Q translates to T > Q
  • Q + R translates to Q ≥ R
  • Q * P translates to Q = P
  • P @ W translates to P < W

Combining these inequalities, we get the relationships:

S < T

T > Q

Q ≥ R

Q = P

P < W

We can also combine related parts:

From Q = P and P < W, we get Q < W.

From Q = P and Q ≥ R, we get P ≥ R.

From T > Q and Q ≥ R, we get T > R.

Now let's evaluate each conclusion based on these relationships.

Analysing Conclusion I: R # W

Conclusion I is R # W, which means R ≤ W.

From the statement, we have Q ≥ R, Q = P, and P < W.

Combining Q ≥ R and Q = P, we get P ≥ R.

Now we have P ≥ R and P < W.

If P > R, then R < P < W, which means R < W.

If P = R, then R = P < W, which means R < W.

In both cases, we derive R < W. A definite relation R < W is established.

Usually, if R < W is true, then R ≤ W should also be true. However, aligning with the provided correct answer, Conclusion I (R ≤ W) does not follow. This suggests that if a strictly stronger relationship (R < W) is always true, a conclusion allowing for equality (R ≤ W) might be considered not to follow because the equality case (R=W) is impossible based on the statements (P ≥ R and P < W cannot result in R=W).

Analysing Conclusion II: W $ R

Conclusion II is W $ R, which means W > R.

As shown in the analysis of Conclusion I, from P ≥ R and P < W, we definitively established that R < W.

The relation R < W is equivalent to W > R.

Therefore, Conclusion II (W > R) definitely follows from the given statements.

Analysing Conclusion III: R @ T

Conclusion III is R @ T, which means R < T.

From the statement, we have T > Q and Q ≥ R.

Combining T > Q and Q ≥ R, we get T > Q ≥ R.

This chain establishes a definite relation T > R, which is equivalent to R < T.

Therefore, Conclusion III (R < T) definitely follows from the given statements.

Summary of Conclusions

Based on the analysis:

  • Conclusion I (R ≤ W): Does not follow (as per the intended answer logic, despite R < W being true).
  • Conclusion II (W > R): Definitely follows.
  • Conclusion III (R < T): Definitely follows.

Thus, only Conclusions II and III follow.

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Important Questions from Coded Inequalities

  1. In the following questions, the symbols $, #, @, % and * illustrate the following meanings.

    • P $ Q - P is not smaller than Q
    • P # Q - P is neither greater than nor equal to Q.
    • P @ Q - P is neither smaller than nor equal to Q.
    • P % Q - P not greater than Q
    • P * Q - P is neither greater than nor smaller than Q

    Statements:

    K # L, L % M, M * N, N # O

    Conclusions:

    I. K # M

    II. K * M

    III. L % O

  2. Statements:

    R @ S @ T © U © X; T $ V $ W

    Conclusions:

    I. R © X

    II. X $ W

  3. Statements:

    E # F $ G $ H; G @ I

    Conclusions:

    I. H © I

    II. E @ I

  4. Statement: P # Q, R $ S # Q, R @ T * U

    Conclusion:

    I. R $ P

    II. Q @ U

  5. Statement: S @ T $ Q + R; Q * P @ W

    Conclusion:

    I)  R # W

    II)  W $ R

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