Statement (I) : Electron lithography offers higher resolution than optical lithography. Statement (II) : Electron lithography has small wavelength of the 10-50 keV electrons.
The question asks us to evaluate two statements regarding electron lithography and optical lithography, specifically focusing on resolution and the reason behind it.
Statement (I) says: "Electron lithography offers higher resolution than optical lithography."
Lithography is a process used to pattern features onto a substrate, like a silicon wafer, in semiconductor manufacturing. Resolution in lithography refers to the minimum feature size that can be reliably printed and the minimum spacing between features. Optical lithography uses light (photons) as the imaging radiation, typically in the deep ultraviolet (DUV) range or even extreme ultraviolet (EUV) for advanced nodes. Electron lithography, or e-beam lithography, uses a beam of electrons.
It is a well-established fact that electron lithography can achieve much higher resolution (patterning smaller features) compared to traditional optical lithography. This is because electrons can be focused to a much smaller spot size than light, and the interaction of electrons with the resist material allows for very fine patterns.
Therefore, Statement (I) is true.
Statement (II) says: "Electron lithography has small wavelength of the 10-50 keV electrons."
Quantum mechanics tells us that particles, including electrons, exhibit wave-like properties. The wavelength associated with a particle is given by the de Broglie wavelength formula:
\(\lambda = \frac{h}{p} = \frac{h}{mv}\)
where:
For electrons accelerated through a potential difference (voltage), their kinetic energy is related to the voltage (V) by \(E = eV\). This energy can also be expressed as \(E = \frac{1}{2}mv^2\). From this, we can find the momentum \(p = mv = \sqrt{2mE}\). Substituting this into the de Broglie wavelength formula gives:
\(\lambda = \frac{h}{\sqrt{2mE}}\)
For relativistic electrons, a more accurate formula is used, but the principle remains: higher electron energy means shorter wavelength. Electrons used in e-beam lithography are typically accelerated to energies between 10 keV and 100 keV. Let's estimate the wavelength for, say, 20 keV electrons (non-relativistic approximation for simplicity, though relativistic effects are significant at higher energies):
\(E = 20 \text{ keV} = 20 \times 10^3 \times 1.602 \times 10^{-19} \text{ J} \approx 3.204 \times 10^{-15} \text{ J}\)
\(h = 6.626 \times 10^{-34} \text{ J}\cdot\text{s}\)
\(m_e = 9.109 \times 10^{-31} \text{ kg}\)
\(\lambda = \frac{6.626 \times 10^{-34}}{\sqrt{2 \times 9.109 \times 10^{-31} \times 3.204 \times 10^{-15}}}\)
\(\lambda \approx \frac{6.626 \times 10^{-34}}{\sqrt{5.836 \times 10^{-45}}} \approx \frac{6.626 \times 10^{-34}}{7.640 \times 10^{-23}} \approx 0.867 \times 10^{-11} \text{ m} = 0.00867 \text{ nm}\)
The calculated wavelength (even with the non-relativistic approximation) is in the picometer to sub-nanometer range. This is orders of magnitude smaller than the wavelength of light used in optical lithography, which is typically hundreds of nanometers (e.g., 193 nm for ArF excimer lasers). Therefore, the statement that 10-50 keV electrons have a small wavelength is true.
Resolution in any imaging or patterning system is fundamentally limited by the wavelength of the radiation used. The smaller the wavelength, the finer the features that can be resolved or patterned. This is analogous to the Rayleigh criterion in optics, although the interaction of electrons with matter is different from that of photons.
Statement (II) correctly points out that electrons used in lithography have very small wavelengths. Statement (I) states that electron lithography achieves higher resolution than optical lithography. The small wavelength of electrons (Statement II) directly explains why electron lithography can produce much finer features and thus has higher resolution (Statement I) compared to optical lithography which uses light with much larger wavelengths.
Therefore, Statement (II) is the correct explanation for Statement (I).
Both Statement (I) and Statement (II) are individually true, and Statement (II) is the correct explanation of Statement (I).
| Feature | Optical Lithography | Electron Lithography |
|---|---|---|
| Radiation Source | Light (Photons) | Electron Beam |
| Typical Wavelength | Hundreds of nanometers (e.g., 193 nm, 248 nm) | Sub-nanometer (for keV electrons) |
| Resolution | Limited by diffraction and wavelength (typically >10 nm for advanced nodes) | Much higher (can achieve <10 nm features) |
| Speed / Throughput | High (parallel exposure) | Low (serial writing) |
| Cost | High (especially for EUV) | High (system and operational) |
| Concept | Explanation | Relevance to Question |
|---|---|---|
| Lithography Resolution | Ability to pattern small features and spaces. | Core property being compared. |
| Electron Wavelength | Wave-like property of electrons, calculated by de Broglie formula. | Key factor determining electron lithography resolution. |
| De Broglie Wavelength | \(\lambda = h/p\). Wavelength inversely proportional to momentum/energy. | Explains why high-energy electrons have small wavelengths. |
| Optical Diffraction Limit | Fundamental limit on resolution for optical systems based on wavelength. | Explains the resolution limitation of optical lithography. |
While electron lithography offers superior resolution, its main drawback for mass manufacturing is its low throughput. It is a serial process, meaning it writes patterns pixel by pixel, which is slow for large areas like a silicon wafer. Optical lithography, on the other hand, is typically a parallel process where an entire mask pattern or a large portion is exposed simultaneously, leading to high throughput. Because of this, optical lithography remains the dominant technique for high-volume production of integrated circuits, pushing towards smaller wavelengths (EUV) and advanced techniques like immersion lithography and multiple patterning to improve resolution.
Electron lithography is primarily used for:
Understanding the trade-offs between resolution, throughput, and cost is crucial when selecting a lithography technique for a specific application.
When once a pocket of smoke, containing air pollutants, is released into the atmosphere from a source like an automobile or a factory chimney, it gets dispersed into the atmosphere into various directions depending upon the
1. prevailing winds
2. temperature
3. pressure conditions
Select the correct answer.
During the compaction test, the weight of compacted soil specimen along with mould is 38.2 N. The volume and weight of mould are 0.95×10-3 m³ and 20.5 N respectively and the water content is 12%. The dry unit weight of the compacted specimen will be nearly