All Exams Test series for 1 year @ ₹349 only
Question

Some equipotential surfaces are shown. What is the magnitude and direction of electric field?

The correct answer is

200 V/m making an angle of 120° with x-axis

Electric field (E) is given by the relation \( E = -\frac{\Delta V}{\Delta x} \). The voltage difference between successive surfaces is 10V, and the distance is 10 cm (0.1 m), so \( E = \frac{10}{0.1} = 100 V/m \). The direction is perpendicular to equipotential lines, leading to an effective angle of 120° with the x-axis.

Was this answer helpful?

Important Questions from Electrostatic Potential and Capacitance

  1. The waves used by artificial satellites for communication purposes are:

  2. The shape of a wavefront when light emerges out of a convex lens after a parallel beam of light is incident on it:

  3. A dielectric material placed in uniform electric field, which of the following option is NOT CORRECT:

  4. A bulb and a capacitor are connected in series to an a.c. source. A dielectric slab is now introduced between the plates of the capacitor. The intensity of the bulb will be:

  5. Eight identical spherical drops, each having a potential of 9V, are combined together to form a single large drop. The potential of this large drop will be:

Need Expert Advice?

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App