Six persons A, B, C, D, E and F work on six different days of a same week from Sunday to Friday (not necessarily in the same order). Three persons work between A and F. Two persons work between B and D. E works on Monday. C works after D, but before F. Which of the following statement is correct? I. B works on Friday. II. C works on Wednesday.
This question is a classic logic puzzle where we need to determine the working day for each of the six persons (A, B, C, D, E, F) based on the given clues. The six days are Sunday through Friday.
The six days available for work are Sunday, Monday, Tuesday, Wednesday, Thursday, and Friday. There is exactly one person working on each of these days. Let's list the days:
The persons are A, B, C, D, E, and F.
We are given the following clues:
Let's start by placing the person with a fixed day based on the clues.
From Clue 3, we know that E works on Monday. Let's place E in our tentative schedule:
| Day | Person |
|---|---|
| Sunday | |
| Monday | E |
| Tuesday | |
| Wednesday | |
| Thursday | |
| Friday |
Now let's use Clue 1: Three persons work between A and F. This means there are exactly three days between A's working day and F's working day. Given there are 6 days (Sunday to Friday), the possible pairs of days for A and F with three days in between are:
However, from Clue 3, E works on Monday. So, neither A nor F can work on Monday. This eliminates the second possibility (Monday and Friday) for the pair A and F.
Therefore, A and F must work on Sunday and Thursday. There are two possibilities:
Let's consider Clue 4: C works after D, but before F. This implies the chronological order of working days is D, then C, then F. D's day < C's day < F's day.
Let's evaluate the two possibilities for A and F:
| Day | Person |
|---|---|
| Sunday | A |
| Monday | E |
| Tuesday | |
| Wednesday | |
| Thursday | F |
| Friday |
Remaining days: Tuesday, Wednesday, Friday. Remaining persons: B, C, D.
From Clue 4 (D -> C -> F), D and C must work before F (Thursday). The available days before Thursday are Tuesday and Wednesday. Thus, D and C must work on Tuesday and Wednesday, with D on Tuesday and C on Wednesday (since D works before C).
This gives us the partial schedule:
| Day | Person |
|---|---|
| Sunday | A |
| Monday | E |
| Tuesday | D |
| Wednesday | C |
| Thursday | F |
| Friday |
The only remaining day is Friday, and the only remaining person is B. So, B must work on Friday.
Proposed schedule:
| Day | Person |
|---|---|
| Sunday | A |
| Monday | E |
| Tuesday | D |
| Wednesday | C |
| Thursday | F |
| Friday | B |
Let's verify this schedule with all the clues:
All clues fit this schedule. This is the correct schedule.
If F works on Sunday, then according to Clue 4 (C works before F), C must work before Sunday. This is not possible as Sunday is the first day of the week in this schedule. So, this possibility is invalid.
Thus, the only possible schedule is:
| Day | Person |
|---|---|
| Sunday | A |
| Monday | E |
| Tuesday | D |
| Wednesday | C |
| Thursday | F |
| Friday | B |
Now we need to check the given statements based on the final schedule.
Statement I: B works on Friday.
Looking at the schedule, B works on Friday. This statement is Correct.
Statement II: C works on Wednesday.
Looking at the schedule, C works on Wednesday. This statement is Correct.
Both statements I and II are correct.
Based on the deduction from the given clues, the final schedule is A on Sunday, E on Monday, D on Tuesday, C on Wednesday, F on Thursday, and B on Friday. Both statement I (B works on Friday) and statement II (C works on Wednesday) are true according to this schedule.
| Day | Person |
|---|---|
| Sunday | A |
| Monday | E |
| Tuesday | D |
| Wednesday | C |
| Thursday | F |
| Friday | B |
Logic puzzles involving scheduling or ordering require careful step-by-step deduction. It's often helpful to:
These types of puzzles are common in aptitude tests and help develop analytical and logical reasoning skills.
A, B, C, D and E are five rivers. A is shorter than B but longer than E. C is the longest and D is a little shorter than B and a little longer than A. Which is the shortest river?
A team of six members is to be selected from ten members M1, M2, M3, M4, M5, M6, M7, M8, M9 and M10. M5 cannot be selected with M10. M6 cannot be selected with M1. M3 to be selected with M9. M4 to be selected with M7. M8 cannot be selected with M5.
Which of the following members can be selected in a team?
Seven games G1, G2, G3, G4, G5, G6 and G7 were played on seven different days of the same week from Monday to Sunday (not necessarily in the same order). Three games were played between G2 and G5. Two games were played between G6 and G4. G3 was played on Tuesday. G2 was played after G4. G7 was played on Friday. G6 was played after G2.
Which of the following statement is correct?
I. No game was played between G2 and G6.
II. G1 was played immediately before G5.
6 teachers P, Q, R, S, T, and U are to deliver the lecture. Each teacher will deliver lectures on one of the days from Monday to Saturday. Each teacher will deliver lectures on different days. There are 3 male and 3 female teachers. Each man is married to a woman. More than two persons deliver between T and U. R delivers on Friday but his wife does not deliver on Monday. P delivered on the next day of S. 2 people present between P and U. P's wife presents P's next day. T and U have the same gender. Which of the following statement is not correct?
Anuj, Ankit, Anu and Alka are teachers who teach Biology, History and Mathematics. Biology is the only subject taught by two teachers, one of whom is male. Two of the four are married to each other and they teach History and Biology respectively. Ankit teaches Biology and is unmarried.
Anu and Alka are females.
Which subject does Anuj teach?