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Question

6 teachers P, Q, R, S, T, and U are to deliver the lecture. Each teacher will deliver lectures on one of the days from Monday to Saturday. Each teacher will deliver lectures on different days. There are 3 male and 3 female teachers. Each man is married to a woman. More than two persons deliver between T and U. R delivers on Friday but his wife does not deliver on Monday. P delivered on the next day of S. 2 people present between P and U. P's wife presents P's next day. T and U have the same gender. Which of the following statement is not correct?

The correct answer is

Two lectures are delivered between Q and S

Teacher Lecture Schedule and Relationship Puzzle Solution

This question requires us to deduce the lecture schedule of six teachers (P, Q, R, S, T, U) over six days (Monday to Saturday) and their marital relationships based on a set of given constraints. We are told there are 3 male and 3 female teachers, forming 3 married couples where each man is married to a woman. Let's break down the information and build the schedule and relationships step-by-step.

Initial Constraints and Placement

  • There are 6 teachers and 6 lecture days (Monday to Saturday).
  • Each teacher lectures on a different day.
  • R delivers on Friday.
  • P delivered on the next day of S (S is immediately before P).
  • There are 2 people between P and U.
  • P's wife lectures the day after P.
  • T and U have the same gender.
  • More than two people deliver between T and U (meaning 3 or 4 people).
  • R's wife does not deliver on Monday.

Let's start placing teachers on the days:

Day Teacher
Monday
Tuesday
Wednesday
Thursday
Friday R
Saturday

Deducing the Lecture Schedule

We know R is on Friday. Let's use the "S followed by P" (S → P) and "2 people between P and U" constraints.

  • S → P means P is one day after S. Possible pairs (S, P) are (Mon, Tue), (Tue, Wed), (Wed, Thu), (Thu, Fri), (Fri, Sat).
  • Since R is on Friday, (Thu, Fri) and (Fri, Sat) are impossible for (S, P).
  • Let's test the remaining options for (S, P) and the "2 people between P and U" rule:
    • If S is Mon, P is Tue. P (Tue) _ _ U. Counting two days after Tuesday (Wed, Thu), U would be on Friday. But R is on Friday. So this is impossible.
    • If S is Tue, P is Wed. P (Wed) _ _ U. Counting two days after Wednesday (Thu, Fri), U would be on Saturday. This is possible. Schedule so far: S(Tue), P(Wed), R(Fri), U(Sat).
    • If S is Wed, P is Thu. P (Thu) _ _ U. Counting two days after Thursday (Fri, Sat), U would be on Sunday. Sunday is not a lecture day. So this is impossible.
  • The only viable schedule fragment is S(Tue), P(Wed), R(Fri), U(Sat).
  • The remaining teachers are Q and T. The remaining days are Monday and Thursday. So Q and T must lecture on Monday and Thursday in some order.

Now let's use the "more than two people between T and U" constraint. U is on Saturday.

  • If T is on Monday: The days between Monday (T) and Saturday (U) are Tuesday, Wednesday, Thursday, Friday. The teachers on these days are S, P, Q, R. That's 4 people between T and U. This satisfies "more than two people".
  • If T is on Thursday: The days between Thursday (T) and Saturday (U) is Friday. The teacher on Friday is R. That's 1 person between T and U. This does not satisfy "more than two people".

Therefore, T must be on Monday. This leaves Q for Thursday.

The complete lecture schedule is:

Day Teacher
Monday T
Tuesday S
Wednesday P
Thursday Q
Friday R
Saturday U

Determining Gender and Relationships

We have 3 male and 3 female teachers, forming 3 couples.

  • P's wife lectures the day after P. P is on Wednesday, the teacher on Thursday is Q. So, Q is P's wife.
  • Since Q is P's wife, P must be male and Q must be female. Couple 1: (P, Q).
  • We are told T and U have the same gender. The remaining teachers are R, S, T, U. We need to identify 2 more males and 2 more females among these four to meet the total count (3M, 3F).
  • If T and U were both male, we would have P(M), T(M), U(M). That's 3 males already. Then R and S must be female. But men are married to women. R(F) would need to be married to a male from S, T, U. Possible males are T, U, S. If R and S are female, they would need husbands from P, T, U. P is married to Q. So R or S would be married to T or U. But T and U are both male in this scenario. This doesn't work with couples (M-F).
  • Therefore, T and U must both be female.
  • With T(F) and U(F), and Q(F), we have 3 female teachers identified. The remaining teachers, R and S, must be male.
  • Genders: P(M), Q(F), R(M), S(M), T(F), U(F). This gives 3 Males and 3 Females.
  • We have couples: (P, Q). The remaining teachers are R(M), S(M), T(F), U(F). The other two couples must be formed from these four. Possible pairings are (R, T), (R, U), (S, T), (S, U).
  • R is male, his wife is female. R's wife does not deliver on Monday. The teacher on Monday is T. So, R's wife is not T.
  • This means R must be married to U. Couple 2: (R, U).
  • The remaining two teachers are S(M) and T(F). They must form the third couple. Couple 3: (S, T).

Final Schedule and Relationships:

Day Teacher Gender Relationship
Monday T Female S's wife
Tuesday S Male T's husband
Wednesday P Male Q's husband
Thursday Q Female P's wife
Friday R Male U's husband
Saturday U Female R's wife

Analyzing the Statements

Now let's evaluate each given statement based on our derived schedule and relationships:

  1. R and U are a married couple: According to our findings, R is married to U. This statement is Correct.
  2. Q is a female teacher and her husband delivers on Wednesday: According to our findings, Q is female and married to P. P delivers on Wednesday. This statement is Correct.
  3. Two lectures are delivered between Q and S: Q delivers on Thursday. S delivers on Tuesday. The lectures between Tuesday (S) and Thursday (Q) is P on Wednesday. Only one lecture (P) is delivered between S and Q. This statement is Incorrect.
  4. S's wife delivers on Monday: According to our findings, S is married to T. T delivers on Monday. This statement is Correct.

The statement that is not correct is "Two lectures are delivered between Q and S".

Revision Table - Teacher Lecture Logic

Constraint/Deduction Result
R delivers on Friday Friday: R
S → P, 2 people between P & U S(Tue), P(Wed), U(Sat)
Remaining days/teachers, More than two between T & U T(Mon), Q(Thu)
P's wife after P Q is P's wife (P-M, Q-F)
3M, 3F; 3 couples; T & U same gender; R's wife not Mon Genders: P(M), Q(F), R(M), S(M), T(F), U(F)
Couples: (P, Q), (R, U), (S, T)

Additional Information - Logic Puzzle Solving

Logic puzzles like this one test your ability to organize information and make deductions based on given rules. Key strategies include:

  • Creating a visual aid like a table or grid to track placements and relationships.
  • Starting with the most direct constraints that fix positions or relationships.
  • Using relative constraints (like 'next day' or 'between') to narrow down possibilities.
  • Testing hypothetical placements or relationships when direct deduction isn't immediately possible (like testing genders for T and U).
  • Using elimination to rule out possibilities that contradict any rule.
  • Checking all original constraints against your final solution to ensure consistency.
  • Carefully reading and evaluating each statement against your verified solution.

Paying close attention to keywords like "between" (inclusive or exclusive - here it means people delivering on days *between* the two mentioned days), "next day", and "more than two" is crucial for accurate deductions in these logic puzzles.

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Important Questions from Scheduling

  1. A, B, C, D and E are five rivers. A is shorter than B but longer than E. C is the longest and D is a little shorter than B and a little longer than A. Which is the shortest river?

  2. A team of six members is to be selected from ten members M1, M2, M3, M4, M5, M6, M7, M8, M9 and M10. M5 cannot be selected with M10. M6 cannot be selected with M1. M3 to be selected with M9. M4 to be selected with M7. M8 cannot be selected with M5.

    Which of the following members can be selected in a team?

  3. Seven games G1, G2, G3, G4, G5, G6 and G7 were played on seven different days of the same week from Monday to Sunday (not necessarily in the same order). Three games were played between G2 and G5. Two games were played between G6 and G4. G3 was played on Tuesday. G2 was played after G4. G7 was played on Friday. G6 was played after G2.

    Which of the following statement is correct?

    I. No game was played between G2 and G6.

    II. G1 was played immediately before G5.

  4. Anuj, Ankit, Anu and Alka are teachers who teach Biology, History and Mathematics. Biology is the only subject taught by two teachers, one of whom is male. Two of the four are married to each other and they teach History and Biology respectively. Ankit teaches Biology and is unmarried.
    Anu and Alka are females.

    Which subject does Anuj teach?

  5. Six persons A, B, C, D, E and F work on six different days of a same week from Sunday to Friday (not necessarily in the same order). Three persons work between A and F. Two persons work between B and D. E works on Monday. C works after D, but before F.

    Which of the following statement is correct?

    I. B works on Friday.

    II. C works on Wednesday.

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