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Question

Simplify $\sqrt[3]{0.216} + \sqrt[3]{0.001} - \sqrt[3]{0.008}$.

The correct answer is
0.5

Simplify Cube Roots Expression

The problem requires simplifying the expression involving cube roots of decimal numbers: $\sqrt[3]{0.216} + \sqrt[3]{0.001} - \sqrt[3]{0.008}$.

Calculate Individual Cube Roots

We need to find the value of each cube root separately:

  • To find $\sqrt[3]{0.216}$: Recognize that $6^3 = 216$. Therefore, $0.6^3 = 0.6 \times 0.6 \times 0.6 = 0.216$. So, $\sqrt[3]{0.216} = 0.6$.
  • To find $\sqrt[3]{0.001}$: Recognize that $1^3 = 1$. Therefore, $0.1^3 = 0.1 \times 0.1 \times 0.1 = 0.001$. So, $\sqrt[3]{0.001} = 0.1$.
  • To find $\sqrt[3]{0.008}$: Recognize that $2^3 = 8$. Therefore, $0.2^3 = 0.2 \times 0.2 \times 0.2 = 0.008$. So, $\sqrt[3]{0.008} = 0.2$.

Combine Results

Now, substitute these values back into the original expression:

$ \sqrt[3]{0.216} + \sqrt[3]{0.001} - \sqrt[3]{0.008} = 0.6 + 0.1 - 0.2 $

Perform the arithmetic operations:

  • Add the first two terms: $0.6 + 0.1 = 0.7$.
  • Subtract the third term from the result: $0.7 - 0.2 = 0.5$.

The simplified value of the expression is $0.5$.

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Important Questions from Simplification

  1. The value of {5 - 5 ÷ (10 - 12) × 8 + 9} × 3 + 5 + 5 × 5 ÷ 5 of 5 is:

  2. What should come in place of the question mark (?) in the following question?

    [((16 ÷ 4) × 4) ÷ 4] = ?

  3. Simplify the following expression.

    \(\frac{{6\frac{1}{2} + 2\frac{5}{7} \times \frac{{14}}{{19}} - \frac{1}{2} \div 2\ of\frac{1}{4}}}{{11 \times 12 \div 12 + 12}}\)

  4. The value of \(\left( {\frac{7}{5} \div \frac{7}{{10}}of\frac{3}{4}} \right) \div \frac{4}{9} + \left( {\frac{7}{{16}} \div 10\frac{1}{2} \times 7\frac{1}{5}} \right) \times \frac{5}{{12}} \)  is:

  5. The value of \(\left( {{1 \over 2}} \right)\) [{–2(12 + 2)}10] is:

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