The goal is to simplify the given expression: $ \frac{\cot\theta - \cos\theta}{\cot\theta + \cos\theta} $ We will use trigonometric identities to simplify this expression.
Recall the identity $\cot\theta = \frac{\cos\theta}{\sin\theta}$. Substitute this into the expression:
$ \frac{\frac{\cos\theta}{\sin\theta} - \cos\theta}{\frac{\cos\theta}{\sin\theta} + \cos\theta} $Factor out the common term $\cos\theta$ from both the numerator and the denominator:
$ \frac{\cos\theta \left( \frac{1}{\sin\theta} - 1 \right)}{\cos\theta \left( \frac{1}{\sin\theta} + 1 \right)} $Cancel the $\cos\theta$ term from the numerator and denominator, assuming $\cos\theta \neq 0$:
$ \frac{\frac{1}{\sin\theta} - 1}{\frac{1}{\sin\theta} + 1} $Use the identity $\csc\theta = \frac{1}{\sin\theta}$. Substitute this into the simplified expression:
$ \frac{\csc\theta - 1}{\csc\theta + 1} $ This simplified form matches option B.What is cos 2β equal to ?
What is the value of sec2γ?
On simplifying \(\frac{{{{\sin }^3}{\rm{A}} + \sin 3{\rm{\;A}}}}{{\sin {\rm{A}}}} + \frac{{{{\cos }^3}{\rm{A}} - \cos 3{\rm{\;A}}}}{{\cos {\rm{A}}}}\) we get
(1 – sin A + cos A) 2is equal to
What is \(\frac{{\cos {\rm{\theta }}}}{{1 - \tan {\rm{\theta }}}} + \frac{{\sin {\rm{\theta }}}}{{1 - \cot {\rm{\theta }}}}\) equal to?