The problem requires simplifying the given trigonometric expression:
$ \frac{(4 + 4 \cot^2 A) \tan A}{(3 + 3 \tan^2 A) \operatorname{cosec} A} $First, factor out the common constants from the numerator and the denominator:
$ \frac{4(1 + \cot^2 A) \tan A}{3(1 + \tan^2 A) \operatorname{cosec} A} $Now, apply the Pythagorean trigonometric identities:
Substitute these identities into the expression:
$ \frac{4(\operatorname{cosec}^2 A) \tan A}{3(\sec^2 A) \operatorname{cosec} A} $Cancel out one $\operatorname{cosec} A$ term from the numerator and denominator:
$ \frac{4 \operatorname{cosec} A \tan A}{3 \sec^2 A} $Rewrite the expression in terms of $\sin A$ and $\cos A$ using the reciprocal and ratio identities:
Substitute these into the expression:
$ \frac{4 \left(\frac{1}{\sin A}\right) \left(\frac{\sin A}{\cos A}\right)}{3 \left(\frac{1}{\cos^2 A}\right)} $Simplify the numerator and the denominator separately:
Now divide the simplified numerator by the simplified denominator:
$ \frac{\frac{4}{\cos A}}{\frac{3}{\cos^2 A}} $To divide, multiply the numerator by the reciprocal of the denominator:
$ \frac{4}{\cos A} \times \frac{\cos^2 A}{3} $Simplify further:
$ \frac{4 \cos^2 A}{3 \cos A} = \frac{4 \cos A}{3} $The simplified expression is $\frac{4 \cos A}{3}$.
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