Shanu walks to his office 5 km away from home. In the morning, he covers the distance in 1 hour whereas, while returning home in the evening, he takes 30 more minutes to cover the same distance. Find his average speed (in km/hr) during the two-way journey.
This question asks us to find the average speed for Shanu's entire two-way journey from home to the office and back. Average speed is calculated by dividing the total distance traveled by the total time taken.
We are given the following information:
To find the average speed, we first need to calculate the total distance Shanu traveled. The journey consists of two parts:
Therefore, the total distance is:
$$ \text{Total Distance} = \text{Distance (to office)} + \text{Distance (back home)} $$ $$ \text{Total Distance} = 5 \text{ km} + 5 \text{ km} = 10 \text{ km} $$
Next, we calculate the total time taken for the entire journey. We need to ensure the time is in consistent units (hours):
The total time is the sum of the time taken for both parts of the journey:
$$ \text{Total Time} = \text{Time (to office)} + \text{Time (back home)} $$ $$ \text{Total Time} = 1 \text{ hour} + 1.5 \text{ hours} = 2.5 \text{ hours} $$
Now we can calculate the average speed using the formula:
$$ \text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}} $$
Plugging in the values we calculated:
$$ \text{Average Speed} = \frac{10 \text{ km}}{2.5 \text{ hours}} $$
To perform the division:
$$ \text{Average Speed} = \frac{10}{2.5} = \frac{100}{25} = 4 $$
So, Shanu's average speed during the two-way journey is 4 km/hr.
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