All Exams Test series for 1 year @ ₹349 only
Question

Shanu walks to his office 5 km away from home. In the morning, he covers the distance in 1 hour whereas, while returning home in the evening, he takes 30 more minutes to cover the same distance. Find his average speed (in km/hr) during the two-way journey.

The correct answer is
4

This question asks us to find the average speed for Shanu's entire two-way journey from home to the office and back. Average speed is calculated by dividing the total distance traveled by the total time taken.

Shanu's Journey Details

We are given the following information:

  • Distance from home to office: 5 km
  • Time taken to travel to the office: 1 hour
  • Time taken to travel back home: 1 hour and 30 minutes

Total Distance Covered

To find the average speed, we first need to calculate the total distance Shanu traveled. The journey consists of two parts:

  • Distance traveled from home to office = 5 km
  • Distance traveled from office to home = 5 km

Therefore, the total distance is:

$$ \text{Total Distance} = \text{Distance (to office)} + \text{Distance (back home)} $$ $$ \text{Total Distance} = 5 \text{ km} + 5 \text{ km} = 10 \text{ km} $$

Total Time Taken

Next, we calculate the total time taken for the entire journey. We need to ensure the time is in consistent units (hours):

  • Time taken to travel to the office = 1 hour
  • Time taken to travel back home = 1 hour and 30 minutes. Since 30 minutes is half an hour, this is $1 + 0.5 = 1.5$ hours.

The total time is the sum of the time taken for both parts of the journey:

$$ \text{Total Time} = \text{Time (to office)} + \text{Time (back home)} $$ $$ \text{Total Time} = 1 \text{ hour} + 1.5 \text{ hours} = 2.5 \text{ hours} $$

Average Speed Calculation

Now we can calculate the average speed using the formula:

$$ \text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}} $$

Plugging in the values we calculated:

$$ \text{Average Speed} = \frac{10 \text{ km}}{2.5 \text{ hours}} $$

To perform the division:

$$ \text{Average Speed} = \frac{10}{2.5} = \frac{100}{25} = 4 $$

So, Shanu's average speed during the two-way journey is 4 km/hr.

Was this answer helpful?

Important Questions from Average Speed

  1. A car covers the first 41 km of its journey in 45 min and covers the remaining 23 km in 35 min. What is the average speed (in m/sec) of the car?

  2. Akhil drives a car from his home to office at an average speed of 50 km/h and reaches office 10 minutes early. But one day due to some problem with the car, he could drive at an average speed of 30 km/h only and reached office 10 minutes late. How far is his office from home ?

  3. During a flight of 900 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 300 km/h and the time of flight increased by 30 min. The original duration of the flight was :

  4. If a man travels from A to B at a speed of 50 km/h and returns by increasing his speed by 40%, then find his average speed (to 2 decimal places) for both the trips.

  5. A man travels a distance of 420 km by train which moves at the speed of 75 km/h and returns back by car at the speed of 50 km/h. Find his average speed for the whole journey.

Need Expert Advice?

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App