This problem asks us to find the current age of Q based on relationships involving the ages of P and Q. We will use algebra to set up and solve equations representing these relationships.
Let $P$ represent the present age of person P, and let $Q$ represent the present age of person Q.
The problem states: "Seven times the present age of P exceeds the present age of Q by 46 years." This translates directly into an algebraic equation:
$7P = Q + 46$
We can rewrite this equation as:
$7P - Q = 46 \quad (1)$
The problem also describes a situation 8 years from now. In 8 years:
The second condition is: "six times Q's age will be 24 years less than six times P's age at that time." This gives us the equation:
$6(Q + 8) = 6(P + 8) - 24$
Let's simplify this equation:
$6Q + 48 = 6P + 48 - 24$
$6Q + 48 = 6P + 24$
Subtracting 48 from both sides:
$6Q = 6P - 24$
Dividing every term by 6 simplifies the equation to:
$Q = P - 4 \quad (2)$
We now have a system of two linear equations:
We can use the substitution method. From equation (2), we can express $P$ in terms of $Q$ as $P = Q + 4$.
Substitute $P = Q + 4$ into equation (1):
$7(Q + 4) - Q = 46$
Distribute the 7:
$7Q + 28 - Q = 46$
Combine the terms involving $Q$:
$6Q + 28 = 46$
Isolate the $Q$ term by subtracting 28 from both sides:
$6Q = 46 - 28$
$6Q = 18$
Solve for $Q$ by dividing by 6:
$Q = \frac{18}{6}$
$Q = 3$
To ensure our answer is correct, let's verify it using the original conditions.
If $Q = 3$, then using $P = Q + 4$, we find $P = 3 + 4 = 7$. So, P is 7 years old and Q is 3 years old.
Is $7 \times P$ equal to $Q + 46$? $7 \times 7 = 49$ $3 + 46 = 49$ Yes, $49 = 49$. Condition 1 holds true.
After 8 years, P will be $7 + 8 = 15$ and Q will be $3 + 8 = 11$.
Is $6 \times (Q \text{'s future age})$ equal to $6 \times (P \text{'s future age}) - 24$? $6 \times 11 = 66$ $6 \times 15 - 24 = 90 - 24 = 66$ Yes, $66 = 66$. Condition 2 holds true.
Since both conditions are satisfied, the calculated present age of Q is correct.
The present age of Q is 3 years.