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Question

If 4 times a son's age is added to his father's age, the sum is 100 years. If 2.5 times the father's age is added to the son's age, the sum is 97 years. What is the father's age (in years)?

The correct answer is
32

Father and Son Age Problem Analysis

This problem requires us to determine the father's age based on two specific relationships given between his age and his son's age. We'll translate these relationships into algebraic equations and solve them systematically.

Formulating Age Equations

Let's denote the son's current age as $S$ and the father's current age as $F$.

The first condition states: "4 times a son's age is added to his father's age, the sum is 100 years." This translates to the equation:

$4S + F = 100$

The second condition states: "2.5 times the father's age is added to the son's age, the sum is 97 years." This gives us the equation:

$S + 2.5F = 97$

Solving for Father's Age

We now have a system of two linear equations:

  1. $4S + F = 100$
  2. $S + 2.5F = 97$

To solve for $F$ (the father's age), we can use the method of elimination. First, let's eliminate $S$. We can multiply the second equation by 4 so that the coefficient of $S$ matches the first equation:

$4 \times (S + 2.5F) = 4 \times 97$

$4S + 10F = 388$ (Equation 3)

Now, we subtract the first equation ($4S + F = 100$) from Equation 3:

$(4S + 10F) - (4S + F) = 388 - 100$

Simplifying the left side:

$4S + 10F - 4S - F = 288$

$9F = 288$

To find $F$, we divide both sides by 9:

$F = \frac{288}{9}$

$F = 32$

Therefore, the father's age is 32 years.

Solution Verification

To ensure our calculation is correct, let's find the son's age using $F = 32$ and the first equation $4S + F = 100$:

$4S + 32 = 100$

$4S = 100 - 32$

$4S = 68$

$S = \frac{68}{4}$

$S = 17$

Now, let's check if these ages ($S = 17$, $F = 32$) satisfy the second condition $S + 2.5F = 97$:

$17 + (2.5 \times 32)$

$17 + 80$

$97$

Since $97 = 97$, our calculated ages satisfy both conditions, confirming the father's age is correct.

Final Father's Age Answer

The father's age is 32 years.

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Important Questions from Problem on Age

  1. Seven times the present age of P exceeds the present age of Q by 46 years. After 8 years, six times Q's age will be 24 years less than six times P's age at that time. What is the present age (in years) of Q?
  2. 3 years ago, the father's age was 24 years more than twice his son's age. After how many years from now will his age be twice his son's age?
  3. 3 years ago, the age of a father was 18 years more than twice his son's age. After how many years, from now, will he be twice his son's age?
  4. 8 years ago, the age of a father was 21 years more than twice his son's age. After how many years, from now, will he be twice his son's age?
  5. Two times the present age of P exceeds the present age of Q by 15 years. After 9 years, twice Q's age will be 14 years less than twice P's age at that time. What is the present age (in years) of Q?
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