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Question

Sets x1, x2, ..., x100 and y1, y2, ..., y150 have means zero and the same standard deviations. Which of the following is the ratio of \(\rm \sum_1^{100} x_i^2\ to \sum_1^{150} y_i^2\) closest to?

The correct answer is

2 ∶ 3

Sets and Standard Deviation

The question provides information about two sets of data, \(x_1, x_2, ..., x_{100}\) and \(y_1, y_2, ..., y_{150}\).

  • The first set, x, contains 100 elements. The number of elements is \(n_x = 100\).
  • The second set, y, contains 150 elements. The number of elements is \(n_y = 150\).
  • Both sets have a mean of zero. This means \(\bar{x} = 0\) and \(\bar{y} = 0\).
  • Both sets have the same standard deviation. Let's denote this standard deviation by \(\sigma\).

We are asked to find the ratio of the sum of squares of elements in set x (\(\sum_{i=1}^{100} x_i^2\)) to the sum of squares of elements in set y (\(\sum_{j=1}^{150} y_j^2\)).

Standard Deviation Formula with Zero Mean

The standard deviation (\(\sigma\)) of a set of \(n\) values \(z_1, z_2, ..., z_n\) with a mean \(\bar{z}\) is typically calculated using the formula:

\(\sigma = \sqrt{\frac{1}{n} \sum_{i=1}^n (z_i - \bar{z})^2}\)

Squaring both sides gives the variance (\(\sigma^2\)):

\(\sigma^2 = \frac{1}{n} \sum_{i=1}^n (z_i - \bar{z})^2\)

When the mean (\(\bar{z}\)) is zero, the term \((z_i - \bar{z})\) simplifies to \(z_i - 0 = z_i\). So, for a set with zero mean, the variance formula becomes:

\(\sigma^2 = \frac{1}{n} \sum_{i=1}^n z_i^2\)

From this simplified formula, we can rearrange to find the sum of squares:

\(\sum_{i=1}^n z_i^2 = n \sigma^2\)

Calculating Sum of Squares for Each Set

Using the derived formula \(\sum z_i^2 = n \sigma^2\):

For the first set (x), with \(n_x = 100\) elements and standard deviation \(\sigma\):

\(\sum_{i=1}^{100} x_i^2 = n_x \sigma^2 = 100 \sigma^2\)

For the second set (y), with \(n_y = 150\) elements and the same standard deviation \(\sigma\):

\(\sum_{j=1}^{150} y_j^2 = n_y \sigma^2 = 150 \sigma^2\)

Determining the Ratio

We need to find the ratio of \(\sum_{i=1}^{100} x_i^2\) to \(\sum_{j=1}^{150} y_j^2\). This is the ratio \(\frac{\sum_{i=1}^{100} x_i^2}{\sum_{j=1}^{150} y_j^2}\).

Substitute the calculated sums of squares:

Ratio = \(\frac{100 \sigma^2}{150 \sigma^2}\)

Since both sets have the same standard deviation, \(\sigma\), the \(\sigma^2\) term cancels out (assuming \(\sigma \neq 0\), otherwise the sum of squares would be 0 for both sets, leading to an undefined ratio unless interpreted as 0:0 which is not an option):

Ratio = \(\frac{100}{150}\)

Simplify the fraction by dividing both the numerator and denominator by their greatest common divisor, which is 50:

Ratio = \(\frac{100 \div 50}{150 \div 50} = \frac{2}{3}\)

The ratio is \(\frac{2}{3}\), which can be written as 2 ∶ 3.

Comparing with Options

Let's compare our calculated ratio 2 ∶ 3 with the given options:

  • Option 1: 1 ∶ 1 (Ratio is 1/1)
  • Option 2: √2 ∶ √3 (Ratio is \(\frac{\sqrt{2}}{\sqrt{3}}\))
  • Option 3: 2 ∶ 3 (Ratio is 2/3)
  • Option 4: 4 ∶ 9 (Ratio is 4/9)

Our calculated ratio 2 ∶ 3 matches Option 3.

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Important Questions from Standard Deviation

  1. A cold drink bottling plant fills bottles of 500 ml. capacity with mean of 500 ml. and a standard deviation of 5 ml. Atleast what percentage of bottles would contain cold drink between 490 ml. and 510 ml.?

  2. The mean and standard deviation of 100 terms are 50 and 3, respectively. The sum of squares of the 100 terms is:

  3. Following are the ages (in years) of 6 people in a group: 25, 30, 35, 40, 45 and 50. What is the standard deviation of their ages (rounded to two decimal places)?
  4. If the mean of a random variable X following Poisson distribution is 3, then standard deviation of the distribution is:

  5. The standard deviation of five numbers is zero. Which of the following must be true?

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