Select the correctly matched pair about sickle cell anaemia: Genotype: Phenotype: (A) HbA HbA : Diseased phenotype (B) HbA HbS : Diseased phenotype (C) HbS HbS : Diseased phenotype (D) HbS HbA : Carrier of disease Choose the correct answer from the options given below:
(C) and (D) only
Sickle cell anaemia is a genetic disorder that affects haemoglobin, the protein in red blood cells that carries oxygen. It is inherited in an autosomal recessive pattern. This means that a person must inherit two copies of the mutated gene to have the disease.
The gene involved is for the beta-globin chain of haemoglobin. The normal allele is denoted as $\text{Hb}^\text{A}$, and the allele causing sickle cell haemoglobin is denoted as $\text{Hb}^\text{S}$.
Let's look at the different genotypes and their corresponding phenotypes:
Now let's evaluate the given pairs based on our understanding of sickle cell anaemia genetics:
This statement is incorrect. The $\text{Hb}^\text{A}\text{Hb}^\text{A}$ genotype results in a normal phenotype, not a diseased one.
This statement is incorrect. The $\text{Hb}^\text{A}\text{Hb}^\text{S}$ genotype results in the carrier phenotype (sickle cell trait), not the full diseased phenotype of sickle cell anaemia.
This statement is correct. The $\text{Hb}^\text{S}\text{Hb}^\text{S}$ genotype is homozygous recessive and causes sickle cell anaemia, which is the diseased phenotype.
This statement is correct. The $\text{Hb}^\text{S}\text{Hb}^\text{A}$ genotype is the same as $\text{Hb}^\text{A}\text{Hb}^\text{S}$, which represents the heterozygous state. Individuals with this genotype are carriers of the sickle cell trait.
Based on our analysis, the correctly matched pairs are (C) and (D).
Pair (C) correctly states that the $\text{Hb}^\text{S}\text{Hb}^\text{S}$ genotype corresponds to the diseased phenotype (sickle cell anaemia).
Pair (D) correctly states that the $\text{Hb}^\text{S}\text{Hb}^\text{A}$ (or $\text{Hb}^\text{A}\text{Hb}^\text{S}$) genotype corresponds to the carrier phenotype (sickle cell trait).
| Genotype | Phenotype | Statement | Correctness |
|---|---|---|---|
| $\text{Hb}^\text{A}\text{Hb}^\text{A}$ | Normal | (A) Diseased phenotype | Incorrect |
| $\text{Hb}^\text{A}\text{Hb}^\text{S}$ | Carrier (Sickle Cell Trait) | (B) Diseased phenotype | Incorrect |
| $\text{Hb}^\text{S}\text{Hb}^\text{S}$ | Diseased (Sickle Cell Anaemia) | (C) Diseased phenotype | Correct |
| $\text{Hb}^\text{S}\text{Hb}^\text{A}$ | Carrier (Sickle Cell Trait) | (D) Carrier of disease | Correct |
Therefore, the option that lists (C) and (D) only as the correctly matched pairs is the correct answer.
| Genotype | Description | Phenotype |
|---|---|---|
| $\text{Hb}^\text{A}\text{Hb}^\text{A}$ | Homozygous for normal haemoglobin allele | Normal (unaffected) |
| $\text{Hb}^\text{A}\text{Hb}^\text{S}$ | Heterozygous (one normal, one sickle allele) | Carrier of Sickle Cell Trait (usually asymptomatic) |
| $\text{Hb}^\text{S}\text{Hb}^\text{S}$ | Homozygous for sickle haemoglobin allele | Sickle Cell Anaemia (diseased) |
Sickle cell anaemia is a classic example of a genetic disorder demonstrating different phenotypes based on zygosity. The $\text{Hb}^\text{S}$ allele arose due to a point mutation in the beta-globin gene, specifically a single nucleotide substitution (A to T) that changes the sixth amino acid from glutamic acid (hydrophilic) to valine (hydrophobic).
Heterozygotes ($\text{Hb}^\text{A}\text{Hb}^\text{S}$), while carriers, have a significant advantage in regions where malaria is prevalent. The sickle trait confers some resistance to malaria, which explains the relatively high frequency of the $\text{Hb}^\text{S}$ allele in these populations despite the severe effects of the homozygous condition ($\text{Hb}^\text{S}\text{Hb}^\text{S}$). This phenomenon is known as heterozygote advantage or balancing selection.
Individuals with sickle cell anaemia ($\text{Hb}^\text{S}\text{Hb}^\text{S}$) can experience various symptoms including chronic pain crises, anaemia, fatigue, increased susceptibility to infections, and organ damage, due to the sickling of red blood cells which obstructs blood flow.
When one of the parents has ‘A’ blood group and the other parent has ‘O’ blood group, then their child can have ______ blood group.
Which of the following represents a test cross in which half the offspring is heterozygous and half would be homozygous recessive?
Which of the following is a recessive trait for garden pea plant?
Which of the following pair of contrasting traits was not studied by Mendel?
Failure of chromatids to segregate during cell division cycle results in:
Down’s syndrome is caused by:
The probability of having a haemophilia carrier daughter by a haemophilia carrier mother and a normal father is:
Which of the following statements are correct about Thalassemia?
A. In β-Thalassemia, production of β-globin chain is affected, and in α-Thalassemia, production of α-globin chain is affected.
B. α-Thalassemia is controlled by two closely linked genes HBA1 and HBA2.
C. The genes HBA1 and HBA2 are located on chromosome 11 of each parent.
D. β-Thalassemia is controlled by a single gene HBB.
Choose the correct answer from the options given below:
Match List-I with List-II:
| List-I | List-II |
|---|---|
| (A) Phenylketonuria | (I) Incomplete dominance |
| (B) Haemophilia | (II) 9:3:3:1 |
| (C) Snapdragon | (III) Pleiotropy |
| (D) Dihybrid cross | (IV) Sex-linked |
Choose the correct answer from the options given below:
Chromosomes in meiocytes of butterflies are: