Refer to the number and symbol series given below and answer the question that follows. Counting to be done from left to right only. (All numbers are single-digit numbers only.) (Left) @ 5 2 & % 1 Ω 4 # 9 7 8 $ 2 ^ 8 ! 3 6 * (Right) If all the symbols are dropped from the series, which of the following will be seventh from the right?
The provided series is: $@ 5 2 & % 1 Ω 4 # 9 7 8 $ 2 ^ 8 ! 3 6 *$. The question asks to remove all symbols and find the seventh element counting from the right end.
First, let's list the symbols present in the series. These are: $@$, $&$, $%$, $Ω$, $#$, $, $^$, $!$, $*$.
Now, we remove these symbols from the original series, keeping only the numbers:
The resulting series consisting only of numbers is: $5 2 1 4 9 7 8 2 8 3 6$. We need to find the seventh element counting from the right.
Let's count from the right:
Therefore, the seventh element from the right, after dropping all symbols, is $9$.
Each of the digits in the number 8642571 is arranged in ascending order from left to right. What will be the sum of the digits which are fourth from the left and second from the right in the new number thus formed?
Refer to the following letter, number, symbol series and answer the question that follows.
(Left) C H * * 8 5 9 * 4 9 1 6 5 L # 5 6 5 £ * K B (Right)
If all the numbers are dropped from the series, which of the following will be fifth from the left?