Rahul invested X rupees for 3 years at a rate of y% interest. Shyam invested the same amount at the same rate for 12 years. Find the ratio of simple interest earned by Rahul to simple interest earned by Shyam. A. 1 ∶ 3 B. 1 ∶ 4 C. 2 ∶ 3 D. 4 ∶ 1
B
This question asks us to find the ratio of simple interest earned by two individuals, Rahul and Shyam, who invested the same principal amount at the same interest rate but for different time periods. We will use the formula for simple interest to calculate the interest earned by each person and then find the ratio.
Simple interest (SI) is calculated only on the principal amount. The formula for simple interest is:
$\text{SI} = \frac{\text{Principal} \times \text{Rate} \times \text{Time}}{100}$
Where:
Rahul invested X rupees for 3 years at a rate of y% per annum.
Principal for Rahul = X rupees
Rate of Interest for Rahul = y%
Time Period for Rahul = 3 years
Simple Interest earned by Rahul ($SI_{\text{Rahul}}$) is:
$SI_{\text{Rahul}} = \frac{X \times y \times 3}{100}$
Shyam invested the same amount (X rupees) at the same rate (y%) for 12 years.
Principal for Shyam = X rupees
Rate of Interest for Shyam = y%
Time Period for Shyam = 12 years
Simple Interest earned by Shyam ($SI_{\text{Shyam}}$) is:
$SI_{\text{Shyam}} = \frac{X \times y \times 12}{100}$
We need to find the ratio of simple interest earned by Rahul to simple interest earned by Shyam. This can be written as $SI_{\text{Rahul}} : SI_{\text{Shyam}}$ or $\frac{SI_{\text{Rahul}}}{SI_{\text{Shyam}}}$.
$\frac{SI_{\text{Rahul}}}{SI_{\text{Shyam}}} = \frac{\frac{X \times y \times 3}{100}}{\frac{X \times y \times 12}{100}}$
To simplify this expression, we can cancel out the common terms in the numerator and the denominator. The terms X, y, and 100 are present in both the numerator and the denominator.
$\frac{SI_{\text{Rahul}}}{SI_{\text{Shyam}}} = \frac{X \times y \times 3}{X \times y \times 12}$
Cancel out X and y:
$\frac{SI_{\text{Rahul}}}{SI_{\text{Shyam}}} = \frac{3}{12}$
Now, simplify the fraction $\frac{3}{12}$ by dividing both the numerator and the denominator by their greatest common divisor, which is 3.
$\frac{3 \div 3}{12 \div 3} = \frac{1}{4}$
So, the ratio of simple interest earned by Rahul to simple interest earned by Shyam is 1:4.
The ratio of simple interest earned by Rahul to simple interest earned by Shyam is 1 : 4.
| Investor | Principal (P) | Rate (R) | Time (T) | Simple Interest (SI) |
|---|---|---|---|---|
| Rahul | X | y% | 3 years | $\frac{X \times y \times 3}{100}$ |
| Shyam | X | y% | 12 years | $\frac{X \times y \times 12}{100}$ |
Ratio = $\frac{SI_{\text{Rahul}}}{SI_{\text{Shyam}}} = \frac{3xy/100}{12xy/100} = \frac{3}{12} = \frac{1}{4}$
| Term | Definition | Formula Component |
|---|---|---|
| Principal | Initial amount invested or borrowed. | P |
| Rate | Percentage of interest charged or earned per year. | R (as %/year) |
| Time | Duration for which money is invested or borrowed. | T (in years) |
| Simple Interest | Interest calculated only on the principal. | SI = (P * R * T) / 100 |
It's important to distinguish between simple interest and compound interest.
This question specifically deals with simple interest, making the calculation straightforward based on the formula SI = PRT/100.
Anil lent a sum of Rs. 5,000 on simple interest for 10 years in such a way that the rate of interest is 6% per annum for the first 2 years, 8% per anmum for the next 2 years and 10% per annum beyond 4 years. How much interest (in Rs.) will he earn at the end of 10 years?
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