To determine the quantity of glucose needed for a 5% solution, we use the definition of a percentage solution (mass/volume).
A 5% solution means there are 5 grams of solute (glucose) in every 100 mL of the final solution.
Identify the required concentration: 5% glucose.
This translates to 5 g of glucose per 100 mL of solution.
Identify the required final volume: 1000 mL.
Set up a proportion or use a direct calculation:
Amount (g) = (Concentration (%) / 100) * Volume (mL)
Amount (g) = (5 / 100) * 1000
Amount (g) = 0.05 * 1000
Amount (g) = 50 g
The molecular weight (180) is not required for calculating the mass needed for a percentage concentration.
Therefore, 50 g of glucose is required.
The friction force exerted by air on a moving body is called ----
A series of processes to joint various parts to get a complete product is known as _____
The fixing of different parts of a machine properly as per the requirement is called _____.
Arrange the following lamps based on the increasing power rating and energy consumption to provide the same level of Illumination or lighting
A. Incandescent Lamp with efficacy of 10 lumens/watt
B. Compact fluorescent lamp (CFL) with efficacy of 60 lumens/watt
C. Halogen lamp with efficacy of 20 lumens/watt
D. Mercury vapour lamp with efficacy of 40 lumens/watt
E. Light Emitting diode (LED) lamp with efficacy of 80 lumens/watt
Choose the correct answer from the options given below: